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2 months ago

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Isaac throws an apple straight up from 1.0 m above the ground, reaching a maximum height of 35 meters. Neglecting air resistance

, what is the ball's velocity when it hits the ground?

2 answers:

Maru [3.3K]2 months ago

6 0

The velocity of the apple right before impact with the ground is approximately 26.2005 m/s, while its initial velocity was about 25.8235 m/s.

So, the final velocity (Vf) equals 26.2005 m/s,
and the initial velocity (Vi) equals 25.8235 m/s.

This difference in velocity arises because the apple was thrown from a starting height of 1 meter.

kicyunya [3.2K]2 months ago

5 0

The speed of the ball upon hitting the ground is roughly 26 m/s.

Additional explanation

Acceleration refers to the change in velocity over time.

$\large {\boxed {a = \frac{v - u}{t} } }$

$\large {\boxed {d = \frac{v + u}{2}~t } }$

a = acceleration (m/s²)

v = final velocity (m/s)

u = initial velocity (m/s)

t = time duration (s)

d = displacement (m)

Let's solve the problem now.

This question involves kinematics.

At the peak height, the ball's velocity is zero meters per second.

Given:

Maximum height, h = 35 m

Velocity at max height = 0 m/s

Gravitational acceleration = 9.8 m/s²

Unknown:

Velocity on reaching the ground, v = ?

Solution:

$v^2 = u^2 + 2gh$

$v^2 = 0^2 + 2(9.8)(35)$

$v^2 = 686$

$v = \sqrt {686}$

$v = 7\sqrt{14} ~ m/s$

$v \approx 26 ~ m/s$

Final statement:

The ball will strike the ground traveling at approximately 26 m/s.

Learn more

Runner's Velocity: brainly.com/question/3813437
Kinetic Energy: brainly.com/question/692781
Acceleration explanation: brainly.com/question/2283922
Car Speed: brainly.com/question/568302

Answer details

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity, Driver, Car, Deceleration, Acceleration, Obstacle, Speed, Time, Rate

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b) The count of blood cells is $N_t=1.04*10^{13}$

Explanation:

From the problem statement, we learn that

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The red blood cell radius is $= \frac{7.5*10^{-6}}{2} = 3.75*10^{-6}m$

The mass is generally represented mathematically as

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Substituting values

$m = 1060 * 0.00546$

$m= 5.7876kg$

Cell mass is $m_c$ = 45% of m

= 0.45 * 5,7876

= 2.60442 kg

The volume of cells is $V_c$ = $\frac{m_c}{\rho_d}$

$= \frac{2.60442}{1125}$

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The white blood cells volume is $V_w$ = 1% of the cells volume

$= \frac{1}{100} * 2.315*10^{-3}$

$= 2.315*10^{-5}m^3$

The volume of a single cell is $V_s = 4 \pi r^3$

$= 4*(3.142) * (3.75*10^{-6})^3$

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The red blood cells volume is $V_r = V_c - V_w$

$=2.315*10^{-3} - 2.315*10^{-5}$

$= 2.29*10^{-3}m^3$

The total red blood cell count is $= \frac{V_r}{V_s}$

$= \frac{2.29 *10^{-3}}{2.21*10^{-16}}$

$= 1.037*10^{13}$

The total white blood cell count is $=\frac{V_w}{V_s}$

$= \frac{2.315 * 10^{-5}}{2.21*10^{-16}}$

$= 1.04*10^{11}$

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