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defon
2 months ago
14

Based on the bond energies for the reaction below, what is the enthalpy of the reaction?HC≡CH (g) + 5/2 O₂ (g) → 2 CO₂ (g) + H₂O

(g)
Chemistry
1 answer:
alisha [2.9K]2 months ago
8 0

Answer:

1219.5 kJ/mol

Explanation:

The calculation for this value requires using the following equation:

ΔHºrxn = Σn * (BE of reactants) - Σn * (BE of products)

ΔHºrxn = [1 * (BE C = C) + 2 * (BE C-H) + 5/2 * (BE O = O)] - [4 * (BE C = O) + 2 * (BE O-H)].

The bond energy (BE) values are:

BE C = C: 839 kJ/mol

BE C-H: 413 kJ/mol

BE O = O: 495 kJ/mol

BE C = O: 799 kJ/mol

BE O-H: 463 kJ/mol

By substituting these values into the equation, you will get:

ΔHºrxn = [1 * 839 + 2 * (413) + 5/2 * (495)] - [4 * (799) + 2 * (463)] = 1219.5 kJ/mol

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