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stealth61
19 days ago
5

Fructose is a type of sugar found in fruits and honey. Analysis of a 2.00-g

Chemistry
1 answer:
Anarel [2.9K]19 days ago
3 0
The molecular formula is C6H12O6.
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Montrel takes a trip to Central America during the winter. He finds out that the temperature in Central America is about the sam
lorasvet [2795]

Answer:

C

Explanation

My teacher mentioned that, for instance, Florida tends to be warm, while Central America can have both hot and cold temperatures, and a jacket isn't necessary. I don't recall many details.

6 0
1 month ago
What fact do scientists believe provides evidence for the big bang theory?a. all comets follow elliptical orbits.b. most extra-s
alisha [2963]

Answer:

D

Reasoning:

This is due to the belief that at one time, the galaxy was condensed into a minute spot and the Big Bang event initiated the universe's expansion, propelling galaxies outward into space, distancing them from one another. Dark energy is theorized to exert the force from the Big Bang that drives this expansion.

8 0
1 month ago
Read 2 more answers
What volume of 0.550 M KBr solution can you make from 100.0 mL of 2.50 M KBr?
castortr0y [3046]
M1V1 = M2V2
(2.50)(100.0) = (0.550)V2
V2 = 455mL

From 100.0 mL of 2.50 M KBr, you can prepare 455 mL of 0.550 M solution.
5 0
2 months ago
Read 2 more answers
The final overall chemical equation is Upper Ca upper O (s) plus upper C upper O subscript 2 (g) right arrow upper C a upper C u
lions [2927]

Answer:

The enthalpy of the second intermediate equation is altered by halving its value and changing the sign.

Explanation:

Let's examine both the first and second intermediate reactions alongside the overall equation concerning the examined process;

First reaction;

Ca (s) + CO₂ (g) + ½O₂ (g) → CaCO₃ (s) ΔH₁ = -812.8 kJ

Second reaction;

2Ca (s) + O₂ (g) → 2CaO (s) ΔH₂ = -1269 kJ

Thus, the overall reaction becomes;

CaO (s) + CO₂ (g) → CaCO₃ (s) ΔH =?

According to Hess's law, which states that the total heat change in a reaction is equal to the sum of the heat changes for each step, we cannot simply sum the enthalpies for this overall reaction. Instead, we obtain the overall enthalpy by halving the second intermediate reaction's enthalpy and changing its sign before adding, as illustrated below;

Enthalpy of Intermediate reaction 1 + ½(-Enthalpy of Intermediate reaction 2) = Enthalpy of Overall reaction

7 0
1 month ago
C2H5OH(aq) + MnO− 4 (aq) → Mn2+(aq) + CH3COOH(aq) of acetic acid from ethanol by the action of permanganate ion in acidic soluti
Tems11 [2777]

Response:

Ethanol serves as a reducing agent.(C_2H_5OH)

The lowest integer coefficient for MnO_4^- in the balanced equation is 4

Clarification:

A redox reaction, or oxidation-reduction reaction, is defined as one in which oxidation and reduction processes occur simultaneously.

Oxidation is the process whereby a substance loses electrons, resulting in an increase in oxidation state. In contrast, reduction entails a substance gaining electrons, leading to a decrease in oxidation state.

Reducing agents enable other substances to undergo reduction while becoming oxidized themselves.

Conversely, oxidizing agents facilitate other substances' oxidation while being reduced in the process.

For the chemical reaction in question, the half-reaction would be:

Oxidation:

Reduction:

To balance the oxygen atoms on both sides

C_2H_5OH(aq)+MnO_4^-(aq)\rightarrow CH_3COOH(aq)+Mn^{2+}(aq)

For oxidation:

For reduction:

C_2H_6O\rightarrow C_2H_4O_2

MnO_4^-\rightarrow Mn^{2+}Then balance the hydrogen atoms on both sides.

  • For oxidation:
For reduction:

C_2H_6O+H_2O\rightarrow C_2H_4O_2

Lastly, balance the charge.MnO_4^-\rightarrow Mn^{2+}+4H_2O

  • For oxidation: For reduction:

C_2H_6O+H_2O\rightarrow C_2H_4O_2+4H^+

To balance the electrons, multiply the oxidation reaction by 5 and the reduction by 4 before combining both equations for a balanced redox reaction.

MnO_4^-+8H^+\rightarrow Mn^{2+}+4H_2OOxidation:

  • Reduction:
The finalized balanced chemical equation in acidic conditions will be:

C_2H_6O+H_2O\rightarrow C_2H_4O_2+4H^++4e^-

MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O

In this redox process, ethanol acts as the reducing agent while the permanganate ion serves as the oxidizing agent.

4 0
15 days ago
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