A farmer is using a rope and pulley to lift a bucket of water from the bottom of a well. the farmer uses a force f1=57.5 n to pu
ll the bucket of water upwards. the total mass of the bucket of water is f2= 3.9kg. -Calculate how much work Wg in J gravity does on the bucket filled with water as the farmer lifts it up the well.
-Calculate the net work Wnet in J done on the bucket of water by the two forces F1 and Fg.
The initial problem cannot be resolved due to the absence of the distance or the length of the rope since work is defined as distance multiplied by force. I can only address the second problem. As the bucket ascends, the gravitational force acts downward, leading to the net force being: Fnet = F1 - Fg Here Fg = mg g is the acceleration due to gravity ( 9.81 m/s^2) Fnet = 57.5 N - (3.9 kg)(9.81) N Fnet = 19.24 N
1) Vf = Vo - gt; Setting Vf = 0 gives Vo = gt, resulting in Vo = 9.8 m/s^2 * 1.5 s = 14.7 m/s. 2) The displacement is calculated as d = Vo*t - gt^2 / 2 = 14.7 m/s * 1.5 - 9.8 m/s^2 * (1.5 s)^2 / 2 = 11.02 m.
