Answer:
Explanation:
The relationship between the new temperature scale and the absolute temperature scale is defined as follows
Aw = 2 K
for K = 273.15 (the freezing point of water on the absolute scale)
Aw = 2 x 273.15 = 546.3 K
Each division of the new scale is equivalent to half that of each division on the absolute scale
each division of the new scale is minimal.
The value of R = 8.314 J per mole per K
Here, per K corresponds to 2Aw
Hence, the value of R in the new scale = 8.314/2 J per mole per Aw
= 4.157 J per mole per Aw
k = R / N
= 4.157 / 6.02 x 10²³
= .69 x 10⁻²³
= 6.9 x 10⁻²⁴ J per molecule per Aw .
The correct equation is (C) H3O+(aq) + C2H3O2−(aq) -> HC2H3O2(aq) + H2O(l). A buffer system is composed of a weak acid and its corresponding salt, effectively stabilizing the pH levels within a solution. The buffer works by adjusting the concentrations of the conjugate acid and base, maintaining the pH constant.
Response:
The cuvette was prepared with the solution so that the spectrometer measures solely the absorbance from the solute. This also means the spectrometer disregards other fluctuations in absorbance that typically arise from the composition of water. The spectrometer focused only on the absorbance of 
as reflected in the spectrum. The reaction between the 
and the 
produces two clear liquids that generate the orange product which leads to the absorbance spectrum. Due to the orange color of the solution, it reflects this hue and others like it, while absorbing blue tones. To isolate the absorption of just the , pre-rinsing the cuvette with the solutions intended for measurement is advisable, along with using a kimwipe to clean any fingerprints that might impact data collection.
Clarification:
The cuvette was prepared with the solution so that the spectrometer measures solely the absorbance from the solute. This also means the spectrometer disregards other fluctuations in absorbance that typically arise from the composition of water. The spectrometer focused only on the absorbance of as reflected in the spectrum.
This procedure entails diluting the 12 molar HCl. To decrease the concentration, we must create an equation to determine how much of the 12M is needed for the 3.5M solution.
12 moles HCl 3.5 moles HCl
——————— = ———————
1 Liter of Soln ‘x’ Liters of Soln
Note that the ratio of 12 moles over 1 liter corresponds to 12 molar; thus, we maintain the original concentration of the HCl. By equating it to the 3.5 over ‘x’, we are still preserving the concentration.
After computation, we determine ‘x’ to be 0.292. This value indicates that within 0.292 liters of our 12 M HCl solution, there are 3.5 moles of HCl. Yet, we are not finished.
0.292 liters of 12 M HCl can create 1 liter of 3.5 M HCl, but the inquiry demands 1.5 liters. To achieve this, multiply 0.292 liters by 1.5, resulting in 0.4375, which denotes the quantity of 12 M HCl necessary to prepare a 1500 mL 3.5 M HCl solution.
Answer:
Explanation:
The concept of mass balance around a distillation tower is utilized.
Each column undergoes mass and component balance, with relevant substitutions and analyses detailed in the attached documents.
