Response:
a. To purify a gypsum sample, you will need the following equipment: Bunsen burner, beaker, filter funnel, stirring rod, and filter paper.
b. Gypsum, a sulfate mineral consisting of calcium sulfate dihydrate, can be purified by following these steps:
1. Add water to the gypsum in a beaker.
2. Stir the mixture thoroughly with the stirring rod.
3. Use the filter paper and filter funnel to remove excess solids from the mixture.
4. Heat the filtered mixture on the Bunsen burner to evaporate the remaining water.
5. After cooling, filter again through the filter paper to obtain pure gypsum.
M1V1 = M2V2
(2.50)(100.0) = (0.550)V2
V2 = 455mL
From 100.0 mL of 2.50 M KBr, you can prepare 455 mL of 0.550 M solution.
Response: The moles in 369 grams of calcium hydroxide are 4.98 moles
Reasoning: Given,
Mass of calcium hydroxide = 369 g
Molar mass of calcium hydroxide = 74.093 g/mole
Formula used:

Now substituting the provided values into this formula, you will find the moles of calcium hydroxide.

Thus, the number of moles in 369 grams of calcium hydroxide is, 4.98 moles
To determine the quantity of moles of gas in the sample of chlorine gas, we utilize the ideal gas equation
which is PV=nRT
n=number of moles
R= gas constant (62.36367 l.torr/k.mol)
P=pressure
V=volume
From the ideal gas equation, we can derive n= PV/RT
n= (328 x5.0)/ (62.36367 x310)= 0.085 moles