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wolverine
4 months ago
7

One tank of gold fish is fed the normal amount of food once a day. A second tank is fed twice a day. A third tank is fed four ti

mes a day during a six week study. The fish's weight is recorded daily. All tanks were of the same size and shape. IV: DV: Control Group:
Chemistry
1 answer:
Tems11 [2.7K]4 months ago
4 0

The inquiry is incomplete; here is the full question:

One tank of goldfish receives the standard amount of feeding once daily, a second tank is given two feedings a day, and a third tank is fed four times daily throughout a six-week experiment. The body fat of the fish is recorded every day.

Independent Variable-

Dependent Variable-

Constants

Control Group-

Answer:

A) The quantity of food given to the goldfish

B) The body fat of the goldfish

C) -Type of fish in the experiment (goldfish)

Time period for feeding the fish (six weeks)

Shape and size of the tanks

D) group of goldfish receiving the standard feeding amount

Explanation:

The objective of the experiment is to assess how the quantity of food affects the body fat of goldfish. Consequently, the amount of food serves as the independent variable while the body fat acts as the dependent variable.

The control group is the one given the standard feeding amount (once daily). All subjects are goldfish, fed over a six-week duration, with all tanks being the same shape and size, establishing the constants in the research.

You might be interested in
Carbon dioxide readily absorbs radiation with an energy of 4.67 x 10-20 J. What is the wavelength and frequency of this radiatio
Tems11 [2777]

Answer:

ν = 7.04 × 10¹³ s⁻¹

λ = 426 nm

This wavelength is included in the visible spectrum.

Explanation:

The connection between the energy of radiation and its frequency is expressed through the Planck-Einstein equation:

E = h × ν

where,

E represents energy

h refers to the Planck constant (6.63 × 10⁻³⁴ J.s)

ν is the frequency

Next, we can determine the frequency,

\nu = \frac{E}{h}= \frac{4.67 \times 10^{-20}J }{6.63 \times 10^{-34}J.s} = 7.04 \times 10^{13} s^{-1}

Frequency and wavelength are interconnected via the subsequent equation:

c = λ × ν

where,

c indicates the speed of light (3.00 × 10⁸ m/s)

λ signifies the wavelength

\lambda = \frac{c}{\nu } =\frac{3.00 \times 10^{8} m/s }{7.04 \times 10^{13} s^{-1} } =4.26 \times 10^{-6}m.\frac{10^{9}nm }{1m} = 426 nm

A wavelength of 426 nm is found within the visible range (approximately 380-740 nm)

7 0
4 months ago
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