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Goryan
1 month ago
15

A 8.5-liter sample of a gas has 1.2 mole of the gas. If 0.65 mole of the gas is added, what is the final volume of the gas? Temp

erature and pressure remain constant. 13 liters 14 liters 18 liters 21 liters
Chemistry
2 answers:
lions [2.9K]1 month ago
8 0

Answer:

I can confirm this calculation is accurate.

Explanation:

Alekssandra [3K]1 month ago
7 0

Answer: 13 liters

Explanation: It is crucial to remember two factors that allow us to carry out this calculation.

Firstly, temperature and pressure must remain unchanged, so these constant values are not considered when calculating volume since they will always be the same.

Secondly, we are dealing with the same gas, with the conditions remaining consistent. Hence, we can proceed.

For 1.2 moles of gas, we have a volume of 8.5 liters. Now, let's determine the volume for 0.65 moles:

0.65 mole * (8.5 liter / 1.2 mole) = 4.25 liters

As we maintain the same gas type, we simply need to total the volumes for each mole amount:

8.5 liters + 4.25 liters = 12.75 liters, which rounds to 13 liters.

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lorasvet [2795]

Response: The increase in temperature is 0.53^0C

Reasoning:

The amount of thermal energy needed to elevate the temperature of a given substance by one degree Celsius is referred to as the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat gained by ice = 5280 J

m = mass of ice = 2.40 kg = 2400 g   (1kg=1000g)

c = heat capacity of water = 4.18J/g^0C

Initial temperature  = T_i

Final temperature = T_f  

Temperature change ,\Delta T=T_f-T_i=?

Substituting the values, we obtain:

5280J=2400g\times 4.18J/g^0C\times \Delta T

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1 month ago
At 800 K, the equilibrium constant, Kp, for the following reaction is 3.2 × 10–7. 2 H2S(g) ⇌ 2 H2(g) + S2(g) A reaction vessel a
Tems11 [2777]

Answer:

0.008945 atm

Explanation:

In the reaction:

2H2S(g) ⇌ 2 H2(g) + S2(g)

Kp is defined as:

Kp = P_{H_{2}}^2P_{S_{2}} / P_{H_{2}S}^2

Where P represents the pressure of each component at equilibrium.

Starting with an initial pressure of H2S at 3.00 atm, the equilibrium concentrations are:

H2S = 3.00 atm - 2X

H2 = 2X

S2 = X

Substituting these values into the equation gives:

3.2x10^{-7} = (2X)^2X / (3-2X)^2

3.2x10^{-7} = 4X^3 / 9- 6X+4X^2

0 = 4X³ - 1.28x10⁻⁶X² + 1.92x10⁻⁶X - 2.88x10⁻⁶

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11 days ago
When 1.34 g Zn(s) reacts with 60.0 mL of 0.750 M HCl(aq), 3.14 kJ of heat are produced. Determine the enthalpy change per mole o
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Answer: The change in enthalpy for each mole of zinc involved in the reaction is 152.4 kJ/mol.

Explanation:

First, we need to determine the moles of Zn and HCl.

\text{Moles of }Zn=\frac{\text{Mass of }Zn}{\text{Molar mass of }Zn}

The molar mass of Zn is 65 g/mole

\text{Moles of }Zn=\frac{1.34g}{65g/mole}=0.0206mole

and,

\text{Moles of }HCl=\text{Concentration of }HCl\times \text{Volume of solution}=0.750M\times 0.0600=0.0450mole

Next, we must identify the limiting reagent and the excess reagent.

The chemical reaction given is:

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According to the balanced reaction we find that

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This leads us to determine that HCl is the excess reagent because the moles provided exceed the required moles, while Zn is limiting and restricts product formation.

Now to find the enthalpy change for each mole of zinc reacting in this reaction.

From the reaction we gather that,[ [TAG_59]]

0.0206 moles of Zn yield heat = 3.14 kJ

This implies that 1 mole of Zn generates heat = \frac{3.14kJ}{0.0206mol}=152.4kJ/mol

Hence, the enthalpy change per mole of zinc involved in this reaction amounts to 152.4 kJ/mol.

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