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Goryan
1 day ago
15

A 8.5-liter sample of a gas has 1.2 mole of the gas. If 0.65 mole of the gas is added, what is the final volume of the gas? Temp

erature and pressure remain constant. 13 liters 14 liters 18 liters 21 liters
Chemistry
2 answers:
lions [985]1 day ago
8 0

Answer:

I can confirm this calculation is accurate.

Explanation:

Alekssandra [968]1 day ago
7 0

Answer: 13 liters

Explanation: It is crucial to remember two factors that allow us to carry out this calculation.

Firstly, temperature and pressure must remain unchanged, so these constant values are not considered when calculating volume since they will always be the same.

Secondly, we are dealing with the same gas, with the conditions remaining consistent. Hence, we can proceed.

For 1.2 moles of gas, we have a volume of 8.5 liters. Now, let's determine the volume for 0.65 moles:

0.65 mole * (8.5 liter / 1.2 mole) = 4.25 liters

As we maintain the same gas type, we simply need to total the volumes for each mole amount:

8.5 liters + 4.25 liters = 12.75 liters, which rounds to 13 liters.

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Consider the following system at equilibrium:
VMariaS [1037]

Answer:

A - Increase (R), Decrease (P), Decrease(q), Triple both (Q) and (R)

B - Increase(P), Increase(q), Decrease (R)

C - Triple (P) and cut (q) down to a third

Explanation:

According to the principle of Le Chatelier, when a system reaches equilibrium and a change is introduced, the system will respond to counteract that change.

Since P and Q are reactants, raising the amount of either one or both without a proportional rise in R (which is a product) will cause the equilibrium to move towards the right. Similarly, if R decreases while P and Q remain constant, this too will push the equilibrium to the right. Thus, Increase(P), Increase(q), and Decrease(R) will lead to a rightward shift in the equilibrium.

Conversely, raising R without increasing P and Q will draw the equilibrium to the left. Likewise, cutting down P and/or Q without a similar reduction in R will shift the equilibrium leftward. Therefore, Increase(R), Decrease(P), Decrease(q), and triple both (Q) and (R) will shift the equilibrium to the left.

If there are equivalent changes in P and Q, with R remaining unchanged, then the equilibrium remains stationary. So, tripling (P) while reducing (q) to one third will not alter the equilibrium.

6 0
3 days ago
Hitesh wants to learn swimming. He brought swimming costumes and a cap. What kind of material should these be made of and why?
alisha [964]

Answer:

Nylon and Spandex (Lycra).

Explanation:

These materials are designed to fit the body, with nylon drying more quickly than other types of fabrics, and Spandex being commonly found in swimming and sports apparel due to its elastic qualities. Both fabrics also wick moisture away and dry rapidly.

With high capacity and enhanced flexibility, nylon and Spandex provide a snug fit to the body and can retain their shape during various activities, making them ideal for swimming.

This explains why these materials are suitable based on the situation given.

3 0
13 days ago
5 grams of NaHCO3 was added to 50 cm3 of 1.5 mol dm-3 hydrochloric acid, causing the temperature to decrease by 6.8 K. What is t
Anarel [852]

The balanced chemical equation for the neutralization of HCl with NaHCO_{3} is:

HCl (aq) + NaHCO_{3}(aq)--> NaCl (aq) + H_{2}O(l)+CO_{2} (g)

Given weight of NaHCO_{3} = 5g

Moles of NaHCO_{3} = 5 g *\frac{1 mol}{84 g} = 0.05952 mol NaHCO_{3}

Volume of HCl solution = 50 cm^{3} * \frac{1 mL}{1cm^{3}} = 50 mL

Assuming the density of the solution is 1.0 g/mL

Mass of HCl solution = 50 g

Overall mass of the solution = 50 g + 5 g = 55 g

To find the heat of neutralization, we calculate:

Q = m C ΔT

where m equals the mass of the solution = 55 g

C represents the specific heat capacity of the solution = 4.184\frac{J}{g. ^{0}C}

ΔT signifies the temperature change = 6.8 K = (6.8 - 273) C = -266.2^{0}C

Q = 55 g * 4.184 \frac{J}{g. K}(6.8K) = 1565 J

The enthalpy of neutralization per mole of NaHCO_{3}

= \frac{1565J}{0.05952 mol} = 26294 \frac{J}{mol}*\frac{1 kJ}{1000J} =26.294kJ/mol

3 0
13 days ago
Read 2 more answers
In an experiment, hydrochloric acid reacted with different volumes of sodium thiosulfate in water. A yellow precipitate was form
KiRa [971]

I predict that there will be an increase in the seconds recorded in the time column. This is because, as more water is mixed with sodium thiosulfate, its concentration diminishes in each flask. Additionally, a lower concentration results in a slower reaction rate since fewer molecules of sodium thiosulfate means there are less frequent collisions with sulfuric acid. With fewer collisions occurring in the reaction, it takes a longer time for the reaction to complete, leading to increased time when sodium thiosulfate is diluted.

Explanation:

I can confirm that this explanation is accurate.

6 0
10 days ago
which intensive physical property is observed when droppings of a person seated inside a closed room has able to reach a person
lions [985]

Answer:

The correct answer is "Speed".

Explanation:

  • An intensive or individualized physical property is identified when "speed" is observed as the excretion of an individual in a confined area, capable of reaching someone one meter away after sneezing or coughing.
  • This measure is represented in the unit of "meter per second", indicating its intensive nature.
5 0
15 days ago
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