1/0.0545. The transformation ratio of primary coil turns to secondary coil turns is directly proportional to the voltage transformation occurring. With 6.0 V on the secondary side (output) and 110 V on the primary side (input), the voltage ratio is calculated as 6/110 = 0.0545. This means for each turn in the primary coil, there are 0.0545 turns in the secondary coil.
Answer:
0.000047N
Explanation:
We know that
intensity (I) = P/ A
Where
P= power
A= Area
Thus, the power absorbed can be calculated as:
Power = Intensity x Area
This equals = 1.4 x 10^3 x(10)
Thus,
14000 Watts = 14 kWatt
However, the radiation pressure can be defined as
time-averaged intensity divided by the speed of light in a vacuum
So,
P = (1.4 x 1000)/c
Also,
F= P x A
Thus,
((1.4 x 1000)/(3 x10^8)) x 10
This results in
=0.000046666N
Rounded to two significant figures gives us
=0.000047 N
Since the absolute values of the charges are identical, the changes in potential energy remain equivalent. Consequently, the changes in kinetic energy will also match. We have:
1 = Ke/Kp = m_e * v_e^2 / m_p * v_p^2, which simplifies to:
v_e/v_p = sqrt(m_p/m_e),
indicating that the velocity of the electron is sqrt(m_p/m_e) times greater than that of the proton.
Answer:
Explanation:
The four wires are arranged in series: this setup indicates that the same current passes through them, while the total voltage from the battery, V0, equals the combined voltages across each resistor:
Additionally, the total resistance for this series configuration is
Using Ohm's law, we can determine the voltage V2 across wire 2:
(1)
Here, I represents the entire current flowing through the circuit, which is calculated as:
By substituting into equation (1), we derive V2:
