A straight wire 20 cm long, carrying a current of 4 A, is in a uniform magnetic field of 0.6 T. What is the force on the wire wh
2 answers:
Answer:
The force of magnetism, F = 0.24 N
Explanation:
The provided information includes:
Current in the wire, I = 4 A
Wire length, L = 20 cm = 0.2 m
Magnetic field strength, B = 0.6 T
Force and magnetic field angle, θ = 30°. The formula for magnetic force is:
F = 0.24 N
Consequently, the force acting on the wire at a 30° angle to the magnetic field is 0.24 N. This completes the solution.
Explanation:
The following data is provided.
Length = 20 cm, current = 4 A
B = 0.6 T, = 30°
Thus, the equation for calculating the force on the wire is as follows.
F =
Substituting the values into this equation yields:
F =
=
= 0.24 N
= 0.2 N
This leads us to the conclusion that the force acting on the wire is 0.2 N.
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Answer:
Jari
Explanation:
To determine who is traveling faster, we need to evaluate their gradients. A steeper slope indicates a higher speed.
For Jari's path, starting point is (0, 0) and (6, 7) is another point.
The gradient is the difference in y divided by the difference in x:
Change in y=7-0=7
Change in x=6-0=6
Thus, the slope equals 7/6.
For Jade, her first point is (0, 10) and another is (6, 16).
Change in y=16-10=6
Change in x=6-0=6
Thus, the slope equals 6/6=1.
It's evident that 7/6 exceeds 6/6 or 1, proving Jari is quicker than Jade.
1) The buoyant force acting on an object submerged in a fluid can be described as:
where
indicates the fluid's density, 
represents the volume of the fluid displaced, and 
signifies the gravitational acceleration.
2) To determine the volume of the displaced fluid, we note that the titanium object is entirely submerged in the fluid (air), thus this volume matches the volume of 1 Kg of titanium, which has a density of
. Using the correlation between density, volume, and mass, we derive
3) We can now revisit the equation in step 1) to compute the buoyant force. Given that the air density is
, this provides us with
4) The weight of 1 Kg of titanium is:
Therefore, the buoyant force is negligible when compared to the weight.
where
2) To determine the volume of the displaced fluid, we note that the titanium object is entirely submerged in the fluid (air), thus this volume matches the volume of 1 Kg of titanium, which has a density of
3) We can now revisit the equation in step 1) to compute the buoyant force. Given that the air density is
4) The weight of 1 Kg of titanium is:
Therefore, the buoyant force is negligible when compared to the weight.