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2 days ago

The light waves have that particular interference from question #1 because they are emitted _____.

Physics

2 answers:

Maru [2.3K]2 days ago

7 0

I’m providing the remainder of your question for clarity,

As lasers consist of stacking light waves that amplify into a larger wave due to CONSTRUCTIVE INTERFERENCE.

Therefore, light waves experience constructive interference
because they are emitted IN PHASE with one another.
This signifies they all reach the same spatial point with identical characteristics and their impacts do not negate each other; rather, they enhance each other’s intensity.

Yuliya22 [2.4K]2 days ago

4 0

Response;

- In phase

Clarification;

Constructive interference occurs when the peaks of two waves coincide (the two waves are in phase), resulting in an amplitude that equals the sum of their individual amplitudes.

This interference arises when waves meet in phase, meaning their oscillations at a specific location move in the same direction, causing the resultant amplitude at that point to be significantly larger than that of a single wave's amplitude.

Consequently, for two waves with identical amplitudes to interfere constructively, the resulting amplitude doubles the amplitude of one wave.

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The density of nuclear matter is about 1018 kg/m3. Given that 1 mL is equal in volume to 1 cm3, what is the density of nuclear m

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Answer:

The density comes out to be $10^{6}$ Mg/µL

Explanation:

Given data:

The density of nuclear matter is approximately $10^{18}$ kg/m³

1 ml corresponds to 1 cm³

To determine:

The density of nuclear matter in Mg/µL

Solution:

We recognize that:

1 Mg equals 1000 kg

Thus, 1 m³ is equal to $10^{6}$ cm³

Moreover, 1 cm³ is equivalent to 1 mL

Thus, we can conclude that 1 mL is equal to 10³ µL

With this, we convert the density as follows:

Density = $10^{18}$ kg/m³

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23 days ago

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A metal object with a mass of 19g is heated to 96c, then transferred to a calorimeter containg 75g of water at 18c. the water an

Yuliya22 [2446]

Let Cp represent the specific heat of the metal object. To find this, we can set up a heat balance equation (heat lost by metal = heat gained by water):

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27 days ago

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As computer structures get smaller and smaller, quantum rules start to create difficulties. Suppose electrons move through a cha

Softa [2035]

Answer:

a) ∆x∆v = 5.78*10^-5

∆v = 1157.08 m/s

b) 4.32*10^{-11}

Explanation:

This problem can be addressed using Heisenberg's uncertainty principle, which is expressed as:

$\Delta x\Delta p \geq \frac{\hbar}{2}$

Where h represents Planck’s constant (6.62*10^-34 J s).

Assuming that the electron's mass remains the same, we proceed as follows:

$\Delta x \Delta (m_ev)=m_e\Delta x\Delta v \geq \frac{\hbar}{2}$

Utilizing the electron's mass (9.61*10^-31 kg) and the uncertainty in position (50 nm), we can compute ∆x∆v and ∆v:

$\Delta x \Delta v\geq\frac{\hbar}{2m_e}=\frac{(1.055*10^{-34}Js)}{2(9.1*10^{-31}kg)}=5.78*10^{-5}\ m^2/s$

$\Delta v\geq\frac{5.78*10^{-5}}{50*10^{-9}m}=1157.08\frac{m}{s}$

If we treat the electron like a classic particle, the time required to cross the channel is determined using the upper limit of the uncertainty in velocity:

$t=\frac{x}{v}=\frac{50*10^{-9}m}{1157.08m/s}=4.32*10^{-11}s$