1. Independent variable: the variable that can be modified and regulated.
the nail polish on Sarah's nails
2. Dependent variable: outcomes that result from the changes in the independent variable.
the duration of the nail polish's longevity
3. <span> Hypothesis: Different brands of nail polish have varied durations before they chip.
</span> 4. Control group: the <span> independent variable remains unchanged in this setup, not subject to variations.
</span> the schedule of when Sarah applies her nail polish (Sarah colors her nails every Sunday for a month)
the specific base coat and top coat (she <span> applies the same bottom coat and top coat with every kind of nail polish)
weekly habits (she ensures the same routine each week so her nails are not treated more harshly on some weeks).
</span> Experimental group: <span> the independent variable is altered for this group
type of nail polish (Essie, OPI, and Sally Hansen)
</span> 6. Constants: the experimenter (Sally), duration of study (one week), her weekly routine, <span> base coat and top coat, </span>
Response:
Clarification:
We need an expression that shows how much water has been drained from the tub. This is represented by v, which indicates how many gallons have flowed out since the plug was taken out. Each gallon removed equates to 8.345 pounds of water, so the weight of the drained water Q in pounds as a function of v can be expressed as:
Where v signifies the number of gallons emptied from the tub.
Have a great day! Let me know if there's anything else I can assist with.
Answer:
Approximately, Hannah has completed 7 laps.
Solution:
Based on the provided details:
The complete distance to run, D = 5000 m
The distance for one lap, x = 400 m
Kara's time taken, 
Hannah's time taken, 
The speed for both Kara and Hannah can be determined as follows:
The time taken for each lap is represented by:
t = 500 s
Thus, the distance that Hannah covers in 't' seconds is given by:
The number of laps completed by Hannah when she overtakes Kara:
≈ 7 laps
Answer:
The electric field strength, E = 45.19 N/C
Explanation:
It is indicated that,
Surface charge density on the first surface, 
Surface charge density on the second surface, 
The electric field at a location between the two surfaces can be calculated as:
Consequently, E = 45.19 N/C
Therefore, the electric field's magnitude at a point between both surfaces is 45.19 N/C.
Answer:
Total energy lost is 16.1 KJ
Explanation:
The heat of vaporization for water is 1.84 J/gK, indicating a loss of energy
The heat loss when cooling from 155 to 100 = 1.84 x 5 x (155 + 273 - 100 + 273) = 506 J
Latent heat of steam = 2260 J/g x 5 g = 11300 J
The heat lost upon cooling from 100 to 0 = 4.18 x 5 x (100 - 0) = 2090 J
The fusion heat is calculated as 336 J/g x 5 g = 1680 J
Heat to cool ice from 0 to -55 = 2.09 J/gK x 5 g x (0 -(-55)) = 574.75 J
Summing all heats gives H of the reaction
506 J + 11300 J + 2090 J + 1680 J + 574.75 J = 16150.75 J = 16.1 KJ
Total energy lost is 16.1 KJ
