Answer:
The flow rate of water is (300000kg/s) = (300000l/s)
Explanation:
To compute the volume of moving fluid per second in the channel, we consider the channel's section, the water depth, and the fluid velocity:
Volume flow rate = 15m × 8m × (2.5m/s) = 300 m³/s
To find the mass or liters of water flowing per second, multiply the volume of circulating fluid by the water's density:
Flow rate of water = (300m³/s) × (1000kg/m³) = (300000kg/s) = (300000l/s)
It is important to note that 1kg of water is approximately equivalent to 1 liter.
Answer:
The separation between Earth and the star is growing.
Explanation:
When we witness the electromagnetic radiation of an object shifting towards the blue spectrum, it indicates that the object is moving closer, which compresses the light waves and decreases the wavelength towards blue, referred to as blueshift.
Conversely, when an object retreats from us rapidly, its light waves are stretched, resulting in a longer wavelength that shifts towards the red part of the spectrum. This shift is termed redshift.
The alteration of wavelength and frequency due to relative motion (approaching or receding) is explained by the Doppler effect.
In this case, since the light we detect from the star has transitioned to the red part of the spectrum, we can infer that it is moving away from Earth, indicating that the distance between the star and Earth is increasing.
The light's wavelength absorbed during the transition is 459 nm. Energy difference between the 5-d and the 6-s sub-levels in gold is expressed as ΔE. Let the wavelength associated with the electron's transition from the 5-d to the 6-s state be λ. The relationship that describes the connection between energy and wavelength is defined as: E = hc/λ, where E stands for photon energy, h represents Planck's constant, c is the speed of light, and λ denotes the wavelength of the photon. Therefore, the absorption wavelength in this transition stands at 459 nm.
A. The horizontal component of velocity is
vx = dx/dt = π - 4πsin(4πt + π/2)
vx = π - 4πsin(0 + π/2)
vx = π - 4π(1)
vx = -3π
b. vy = 4πcos(4πt + π/2)
vy = 0
c. m = sin(4πt + π/2) / [πt + cos(4πt + π/2)]
d. m = sin(4π/6 + π/2) / [π/6 + cos(4π/6 + π/2)]
e. t = -1.0
f. t = -0.35
g. To find t, set
vx = π - 4πsin(4πt + π/2) = 0
Then use this to calculate vxmax
h. To determine t, set
vy = 4πcos(4πt + π/2) = 0
Then use this to find vymax
i. s(t) = [x(t)^2 + y(t)^2]^(1/2)
h. s'(t) = d[x(t)^2 + y(t)^2]^(1/2) / dt
k and l. Determine the values for t
d[x(t)^2 + y(t)^2]^(1/2) / dt = 0
And substitute to find both the maximum and minimum speeds.
The Pythagorean Theorem can be utilized here: Imagine a car navigating through traffic—when it turns left to travel north, a right angle of 90 degrees is formed. However, the displacement is always the shortest distance connecting the origin and the endpoint, which forms a triangle in this scenario. In a right triangle, the Pythagorean theorem applies: 215^2+45^2=c^2; therefore, v=√(215^2+45^2).
