A string is stretched by two equal but opposite forces f newton each what is tension in string

1 answer:

8 0

The string does not experience any force of tension, as it balances two forces acting in the same direction. Hence, the tension is zero.

Explanation:

If tension existed in the string, it would mean that two equal but opposite forces are exerting pull in contrary directions.

When a force of f newtons is applied from the right and another force of f newtons from the left, the resulting action occurs through one force. Because there is action on the same string in opposing directions, the tension in the string can only be equal to the magnitude of the string itself.

Therefore, the string indeed has no tension since it is dealing with two forces acting in the same direction. Thus, the tension is zero.

Answer:

The wire length is 32 inches.

Explanation:

According to the question,

The pipe's length = 60 inches

The pipe's circumference = 4 inches

Now,

The wire wraps around the pipe for 8 complete turns.

Now, with 2πr = 4, we find that

r = 2/π

Thus,

The radius, r = 2/π

The wire's length can be calculated as,

Length = Number of turns x Circumference of the pipe

So, length of wire = 8 x 4 = 32 inches.

Consequently, the wire length is 32 inches.

7 0

1 month ago

Read 2 more answers

A roundabout in a fairground requires an input power of 2.5 kW when operating at a constant angular velocity of 0.47 rad s–1 . (

ValentinkaMS [3465]

Since the roundabout operates at a constant angular velocity, the input power equals the frictional power. Given that the frictional power is 2.5 kW, we can express this as frictional torque multiplied by angular velocity: frictional torque x 0.47 = 2.5 kW. Therefore, solving for frictional torque gives us 2.5 / 0.47 kN.m, which amounts to approximately 5.32 kN.m, leading to a rounded value of 5 kN.m. When the power supply is interrupted, the roundabout experiences deceleration due to the influence of the frictional torque.

5 0

24 days ago

Assume that the cart is free to roll without friction and that the coefficient of static friction between the block and the cart

Keith_Richards [3271]

Answer: $F=\frac{(M+m)g}{\mu _s}$