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Goryan
1 month ago
8

A 45.0-kg sample of ice is at 0.00°C. How much heat is needed to melt it? For water, Lf=334 kJ/kg and Lv=2257 kJ/kg 

Physics
2 answers:
ValentinkaMS [3.4K]1 month ago
7 0
The heat necessary to convert ice to liquid is expressed by the formula Q = m* L

where

m = the mass of ice

L = the latent heat of fusion

Given that

m = 45 kg

L = 334 KJ/kg

Using this formula, we can compute the value

Q = 45 * 334 * 10^3

Q = 1.5 * 10^7 J

The answer is stated in KJ as well

Q = 1.5 * 10^4 kJ

the final answer aligns with option D.

Softa [3K]1 month ago
6 0
H=ml
H=334×45.0
Thermal Energy= 15030kJ

or expressed as 1.50×10^4kJ

Answer: D

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A particular brand of gasoline has a density of 0.737 g/mLg/mL at 25 ∘C∘C. How many grams of this gasoline would fill a 14.9 gal
Yuliya22 [3333]

Answer:

The answer to your inquiry is Mass = 41230.7 g or 41.23 kg.

Explanation:

Data

Density = 0.737 g/ml

Mass = ?

Volume = 14.9 gal

1 gal = 3.78 l

Process

1.- Convert gallons to liters

1 gal ---------------- 3.78 l

14.9 gal ------------- x

x = 56.44 l

2.- Convert liters to milliliters

1 l ------------------- 1000 ml

56.44 l --------------- x

x = (56.44 x 1000) / 1

x = 56444 ml

3.- Calculate the mass

Formula

Density = \frac{mass}{volume}

Solving for mass

Mass = density x volume

Substituting values

Mass = 0.737 x 56444

Result

Mass = 41230.7 g or 41.23 kg.

3 0
3 months ago
50 POINTS! A Boy throws a ball horizontally a distance of 22m downrange from the top of a tower that is 20.0m tall. What is his
Softa [3030]

At time t, the ball's horizontal and vertical velocities can be represented as

v_x=v_{xi}

v_y=v_{yi}-gt

However, since the ball is thrown horizontally, we have v_{yi}=0. The horizontal and vertical positions at time t are

x=v_{xi}t

y=20.0\,\mathrm m-\dfrac g2t^2

The ball travels a distance of 22 m horizontally from the throw point, thus

22\,\mathrm m=v_{xi}t

With this, we determine that the time for the ball to reach the ground is

t=\dfrac{22\,\rm m}{v_{xi}}

When it touches down, y=0 and

0=20.0\,\mathrm m-\dfrac{9.8\frac{\rm m}{\mathrm s^2}}2\left(\dfrac{22\,\rm m}{v_{xi}}\right)^2

\implies v_i=v_{xi}=11\dfrac{\rm m}{\rm s}

7 0
1 month ago
A 1,300 kg wrecking ball hits the building at 1.07 m/s2.
ValentinkaMS [3465]
We know that F=ma
where m represents mass and a indicates acceleration
thus, Force= ma
therefore, F=1300X1.07=1391N
I hope this helps
if my answer assists you, please consider marking it as the best one
7 0
2 months ago
Read 2 more answers
Lamar has been running sprints to prepare for his next football game.He has found that he can maintain his maximum speed for 45
Sav [3153]

Answer:

Please refer to the explanation

Explanation:

Race distance is 5km

Top speed = 45 yards

Converting yards to kilometers:

1km equals 1093.613 yards

x = 45 yards

(1093.613 * x) = 45

x = 45 / 1093.613

x = 0.0411480 km

Where x indicates the maximum distance he can sustain his highest speed in kilometers.

Thus, from the data available, we can determine that Lamar will not be able to maintain his maximum speed for the full 5km race, as he can only sustain it for 0.0411 kilometers.

5 0
2 months ago
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