The force exerted on the car during the stop measures 6975 N.
Explanation: Given that the mass (m) is 930 kg, speed (s) at 56 km/h converts to 15 m/s, and the stopping time (t) is 2 s, we compute the force using F = m * a. Here, acceleration (a) can be obtained through a = s/t. The total force calculation confirms that F = 930 kg * (15 m/s) / 2 s results in 6975 N.
Response:
Clarification:
Provided
weight of disk 
diameter of disc 
weight of ring 
Force 
Overall moment of inertia
=Disc's moment of inertia +Ring's Moment of Inertia
At this point, Torque is 
Utilizing 
in this scenario
To address this problem, Boyle's Law must be applied, which states that the initial and final pressures and volumes are related as follows: Where, P₀ and V₀ represent the initial pressure and volume, while P and V refer to the final pressure and volume. The endpoint pressure in this scenario is atmospheric pressure. Thus, using the given equation, we can find the volume the lungs would occupy at the surface.
Answer:
b = 0.6487 kg / s
Explanation:
In the context of oscillatory motion, friction is related to velocity,
fr = - b v
where b represents the friction coefficient.
Upon solving the equation, the angular velocity is represented as
w² = k / m - (b / 2m)²
In this case, we're given an angular frequency w = 1Hz, the mass m = 0.1 kg, and the spring constant k = 5 N / m. This allows us to derive the friction coefficient.
Let’s denote
w₀² = k / m
w² = w₀² - b² / 4m²
b² = (w₀² -w²) 4 m²
Now, let's calculate the angular frequencies.
w₀² = 5 / 0.1
w₀² = 50
w = 2π f
w = 2π 1
w = 6.2832 rad / s
Substituting values yields
b² = (50 - 6.2832²) 4 0.1²
b = √ 0.42086
b = 0.6487 kg / s
