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olga2289
3 months ago
7

If a beaker of water is placed under a broiler so that the heating coil is above the beaker. It is observed that only the surfac

e layer boils. The water at the bottom of the beaker remains close to the initial temperature of the water. Which of the following statements is the most reasonable conclusion to be drawn from these observations?
a) Water is a poor conductor of heat.
b) The sample must contain impurities.
c) Water is easily heated by radiation.
d) Water exhibits anomalous thermal behavior.
e) The molecular motion in the sample is not random.
Physics
1 answer:
ValentinkaMS [3.4K]3 months ago
5 0

Answer:

a

Explanation:

The most plausible interpretation of the observations is that water has poor heat conductivity, essentially acting as an insulator. Heat takes a considerable time to transfer from the surface to the bottom of the beaker. Additionally, since no convection currents are formed, heat may not even reach the bottom. Hydrogen bonding significantly affects the thermal characteristics of water.

Therefore, option A is the correct choice.

You might be interested in
Platinum (pt) has the fcc crystal structure, an atomic radius of 0.1387 nm, and an atomic weight of 195.08 g/mol. what is its th
inna [3103]
The formula to apply is expressed as:

ρ = nA/VcNₐ
where
ρ signifies density
n represents the number of atoms within a unit cell (for FCC, n=4)
A indicates the atomic weight
Vc stands for the cubic cell volume equal to a³, with a being the side length (for FCC, a = 4r/√2, where r is the radius)\
Nₐ denotes Avogadro's number, which is 6.022×10²³ atoms/mol

Calculating the radius: r = 0.1387 nm*(10⁻⁹ m/nm)*(100 cm/1m) = 1.387×10⁻⁸ cm
Then find a: a = 4(1.387×10⁻⁸ cm)/√2 = 3.923×10⁻⁸ cm
Then calculate V: V = a³ = (3.923×10⁻⁸ cm)³ = 6.0376×10⁻²³ cm³

Now compute density:
ρ = [(4 atoms)(195.08 g/mol)]/[(6.0376×10⁻²³ cm³)(6.022×10²³ atoms/mol)]Finally, we get ρ = 21.46 g/cm³
7 0
2 months ago
Read 2 more answers
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