Enter the balanced complete ionic equation for k2so4(aq)+cai2(aq)→caso4(s)+ki(aq). express your answer as a chemical equation. i

Question

Alex73

2 months ago

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Enter the balanced complete ionic equation for k2so4(aq)+cai2(aq)→caso4(s)+ki(aq). express your answer as a chemical equation. i

dentify all of the phases in your answer.

Chemistry

2 answers:

KiRa [2.9K] · Answer 1 · 2026-02-18T00:07:09+03:00

The ionic equation for the reaction is shown below:

Ca^2+(aq) + SO4^2-(aq) → CaSO4(s)

EXPLANATION

K2SO4(aq) + CaI2(aq) → CaSO4(s) + KI(aq)

The ionic representation is:

2K^+(aq) + SO4^2-(aq) + Ca^2+(aq) + 2I^-(aq) → CaSO4(s) + 2K^+(aq) + 2I^-(aq)

Removing the spectator ions (2K^+ and 2I^-), the simplified net ionic equation becomes:

Ca^2+(aq) + SO4^2-(aq) → CaSO4(s)

alisha [2.9K] · Answer 2 · 2026-02-18T00:07:31+03:00

Balanced complete ionic equation:

$\boxed{2{{\text{K}}^+}\left({aq}\right)+{\text{SO}}_4^{2-}\left( {aq} \right) + {\text{C}}{{\text{a}}^{2 + }}\left( {aq} \right) + 2{{\text{I}}^-}\left( {aq}\right)\to{\text{CaS}}{{\text{O}}_4}\left(s\right)+2{{\text{K}}^+}\left({aq}\right)+2{{\text{I}}^-}\left( {aq}\right)}$

${{\text{K}}^+}$ , ${\text{SO}}_4^{2-}$ , ${{\text{I}}^-}$ , and ${\text{C}}{{\text{a}}^{2+}}$ occur in the aqueous phase, whereas ${\text{CaS}}{{\text{O}}_4}$ is in the solid form.

Explanation:

A double displacement reaction involves the swapping of ions between two compounds, forming new products. For compounds AX and BY, the general reaction is:

${\text{AX}}+{\text{BY}}\to{\text{AY}}+{\text{BX}}$

There are three ways to express such reactions:

1. Molecular equation

2. Complete ionic equation

3. Net ionic equation

The molecular equation shows reactants and products as whole compounds. The complete ionic equation breaks aqueous compounds into their ions. The net ionic equation includes only the ions that actively react.

Steps to write the complete ionic equation:

Step 1: Write the molecular equation including phase labels.

In this case, ${{\text{K}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}$ reacts with ${\text{Ca}}{{\text{I}}_2}$ producing ${\text{CaS}}{{\text{O}}_{\text{4}}}$ and KI. The balanced molecular reaction is:

${{\text{K}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\left({aq}\right)+{\text{Ca}}{{\text{I}}_2}\left( {aq} \right) \to {\text{CaS}}{{\text{O}}_{\text{4}}}\left(s\right) + 2{\text{KI}}\left({aq}\right)$

Step 2: Break all aqueous compounds into ions to form the complete ionic equation. Solid and liquid compounds remain intact:

$2{{\text{K}}^+}\left({aq}\right)+{\text{SO}}_4^{2-}\left({aq}\right)+{\text{C}}{{\text{a}}^{2 + }}\left( {aq}\right)+2{{\text{I}}^-}\left( {aq}\right)\to{\text{CaS}}{{\text{O}}_4}\left( s \right) + 2{{\text{K}}^+}\left({aq}\right)+2{{\text{I}}^-}\left( {aq} \right)$

The resulting balanced complete ionic equation is:

$2{{\text{K}}^+}\left( {aq}\right)+{\text{SO}}_4^{2-}\left({aq}\right)+{\text{C}}{{\text{a}}^{2+}}\left( {aq}\right)+2{{\text{I}}^-}\left({aq}\right)\to{\text{CaS}}{{\text{O}}_4}\left( s \right)+2{{\text{K}}^+}\left({aq}\right)+2{{\text{I}}^ - }\left( {aq}\right)$

${{\text{K}}^+}$ , ${\text{SO}}_4^{2-}$ , ${{\text{I}}^-}$ , and ${\text{C}}{{\text{a}}^{2+}}$ exist in aqueous solution, while ${\text{CaS}}{{\text{O}}_4}$ is a solid.

Additional resources:

1. Balanced chemical equations: brainly.com/question/1405182

2. Oxidation and reduction reactions: brainly.com/question/2973661

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical reactions and equations

Keywords: Double displacement reaction, types of chemical equations, molecular, complete ionic, net ionic, K2SO4, CaI2, KI, I-, K+, SO42-, Ca2+, CaSO4, phases, aqueous, solid.