Children’s chewable tylenol contains 80 mg of acetaminophen per tablet. if the recommended dosage is 10 mg/kg, how many tablets

The amino acids classified under the first group include alanine, aspartate, and glutamate, whereas those in the second group consist of glycine, valine, proline, leucine, isoleucine, methionine, serine, threonine, cysteine, asparagine, glutamine, phenylalanine, tryptophan, tyrosine, lysine, arginine, and histidine.

Respuesta:

737.52 mL de agua

Justificación:

En este escenario, es necesario aplicar la fórmula de molaridad de una solución, que es:

M = moles / V

Donde:

V: Volumen de la solución.

Ya que deseamos determinar la cantidad de agua, en otras palabras, buscamos el volumen del solvente que se utilizó para crear los 800 mL de la disolución.

Una disolución se compone de un soluto y un solvente. El soluto que tenemos es nitrato de plata. Utilizando la fórmula mencionada, calculamos los moles de soluto y luego su masa. Tras eso, calculamos el volumen a partir de la densidad y, al final, determinamos la cantidad de solvente de esta manera:

V ste = Vsol - Vsto

Primero, vamos a calcular los moles de soluto:

moles = M * V

moles = 2 * 0.800 = 1.6 moles

Con este número de moles, obtenemos la masa utilizando el peso molecular que es 169.87 g/mol:

m = moles * PM

m = 1.6 * 169.87 = 271.792 g

Usando el valor de densidad, procederemos a calcular el volumen de soluto utilizado:

d = m/V

V = m/d

V = 271.792 / 4.35

V = 62.48 mL

Por último, la cantidad de agua requerida es:

V agua = 800 - 62.48

V agua = 737.52 mL

Answer: Copper is being oxidized and acts as a reducing agent. In contrast, silver is being reduced, functioning as the oxidizing agent.

Explanation:

An oxidation reaction involves the loss of electrons by an atom. Here, the oxidation state of the atom rises.

Conversely, a reduction reaction is characterized by an atom gaining electrons, resulting in a decrease in its oxidation state.

Oxidizing agents are those that facilitate the oxidation of another substance while themselves being reduced. These substances participate in reduction reactions.

Reducing agentsare defined as those that reduce other substances while undergoing oxidation themselves. They also take part in reduction reactions.

In the provided chemical reaction:

The associated half-reactions for the above process are:

Oxidation half reaction:  

Reduction half reaction:  

From the reactions outlined, copper is losing electrons. Consequently, it is oxidized and regarded as a reducing agent.

Silver is acquiring electrons, thus it is being reduced and viewed as an oxidizing agent.

The question lacks completeness; the full question is:

Determine the theoretical yield:

When excess aqueous copper(II) nitrate reacts with aqueous sodium sulfide, sodium nitrate and copper(II) sulfide precipitate. For this reaction, 469 grams of copper(II) nitrate was combined with 156 grams of sodium sulfide yielding 272 grams of sodium nitrate.

Answer:

The theoretical yield of sodium nitrate is 340 grams.

Explanation:

Calculating moles of copper(II) nitrate =

Moles of sodium sulfide =

Based on the reaction, 1 mole of copper(II) nitrate reacts with 1 mole of sodium sulfide.

Thus, 2 moles of sodium sulfide will react with:

of copper(II) nitrate

Since sodium sulfide is in limiting quantities, the amount of sodium nitrate produced will depend on the moles of sodium sulfide available.

According to the reaction, 1 mole of sodium sulfide generates 2 moles of sodium nitrate; thus, 2 moles of sodium sulfide will yield:

sodium nitrate

The total mass of 4 moles of sodium nitrate is:

85 g/mol × 4 mol = 340 g

The theoretical yield of sodium nitrate amounts to 340 g.

The theoretical yield of sodium nitrate is 340 grams.

⁴⁰Ar
N(e)=18
N(p)=18
N(n)=40-18=22

⁴⁰K
N(e)=19
N(p)=19
N(n)=40-19=21

⁴⁰Ca
N(e)=20
N(p)=20
N(n)=40-20=20