Answer:
710.33 g NO2
Explanation:
2 C8H18 + 25 O2 → 16 CO2 + 18 H2O
(800 g octane) / (114.2293 g C8H18/mol x (25/2)) = 87.54 mol O2 utilized for combusting octane
= 15.44 mol O2 used for generating NO2
O2 + 2NO → 2NO2
(15.44 mol O2) x (2/2) x (46.0056 g NO2/mol) = 710.33 g NO2
The inquiry is incomplete; here is the full question:
One tank of goldfish receives the standard amount of feeding once daily, a second tank is given two feedings a day, and a third tank is fed four times daily throughout a six-week experiment. The body fat of the fish is recorded every day.
Independent Variable-
Dependent Variable-
Constants
Control Group-
Answer:
A) The quantity of food given to the goldfish
B) The body fat of the goldfish
C) -Type of fish in the experiment (goldfish)
Time period for feeding the fish (six weeks)
Shape and size of the tanks
D) group of goldfish receiving the standard feeding amount
Explanation:
The objective of the experiment is to assess how the quantity of food affects the body fat of goldfish. Consequently, the amount of food serves as the independent variable while the body fat acts as the dependent variable.
The control group is the one given the standard feeding amount (once daily). All subjects are goldfish, fed over a six-week duration, with all tanks being the same shape and size, establishing the constants in the research.
Answer: 0.0007 moles of 
are released when the temperature rises.
Explanation:
To determine the moles, we utilize the ideal gas law, as follows:
where,
P = gas pressure = 1.01 bar
V = gas volume = 1L
R = gas constant = 
- Calculated moles at T = 20° C
The gas temperature = 20° C = (273 + 20)K = 293K
Substituting values into the equation gives:
- Calculated moles at T = 25° C
The gas temperature = 25° C = (273 + 25)K = 298K
Substituting values into the equation gives:
- Released moles =
Therefore, 0.0007 moles of are released when the temperature increases from 20° C to 25° C.
