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3 months ago

The ________ orbital is degenerate with 5py in a many-electron atom.

Chemistry

1 answer:

Tems11 [2.7K]3 months ago

5 0

The ________ orbital shares degeneracy with 5py in a multi-electron atom.

5px is the right choice

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A compound that is composed of carbon, hydrogen, and oxygen contains 70.6% C, 5.9% H, and 23.5% O by mass. The molecular weight

Tems11 [2777]

Answer: The molecular formula will be $C_8H_8O_2$

Explanation:

When percentages are provided, we assume the total mass to be 100 grams.

Thus, the mass of each element corresponds to the specified percentage.

Mass of C= 70.6 g

Mass of H = 5.9 g

Mass of O = 23.5 g

Step 1: convert given masses to moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{70.6g}{12g/mole}=5.9moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{5.9g}{1g/mole}=5.9moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{23.5g}{16g/mole}=1.5moles$

Step 2: For determining the mole ratio, divide each molar amount by the smallest number of moles calculated.

For C = $\frac{5.9}{1.5}=4$

For H = $\frac{5.9}{1.5}=4$

For O = $\frac{1.5}{1.5}=1$

The resulting ratio of C: H: O= 4: 4: 1

Hence, the empirical formula obtained is $C_4H_4O$

The empirical weight is calculated as $C_4H_4O$ = 4(12)+4(1)+1(16)= 68g.

The molecular weight = 136 g/mole

Now the molecular formula needs to be obtained.

$n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{136}{68}=2$

The molecular formula can be derived as= $2\times C_4H_4O=C_8H_8O_2$

4 0

3 months ago

Consider butter (density= 0.860 g/mL) and sand (density= 2.28 g/mL). If 1.00 mL of butter were mixed with 1.00 mL of sand and mi

Anarel [2989]

The mixture’s density is 1.57 g/cm³.

Step 1: Determine the mass of the butter.

$\text{Mass} = \text{1.00 cm}^{3 } \times \frac{\text{0.680 g} }{\text{1 cm}^{3 }} = \text{0.860 g}\\$

Step 2: Determine the mass of the sand.

$\text{Mass} = \text{1.00 cm}^{3 } \times \frac{\text{2.28 g} }{\text{1 cm}^{3 }} = \text{2.28 g}\\$

Step 3: Determine the density of the mixture.

Total mass = 0.860 g + 2.28 g = 3.14 g.

Total volume = 1 cm³ + 1 cm³ = 2 cm³

$\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{\text{3.14 g} }{\text{2 cm}^{3 }} = \textbf{1.57 g/cm}{^{3}\\$

6 0

3 months ago

A person loses 2.70 lbs in two weeks how many grams did he lose?

VMariaS [2998]

He lost 1224.7 grams.

6 0

4 months ago

Read 2 more answers