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2 months ago

What should you do if the high power objective lens touches or breaks the cover slip?

2 answers:

6 0

Answer : When this occurs, refrain from using the high power objective lens and opt for alternative lenses with different magnifications.

It's essential to handle the compound microscope cautiously. If the high power objective lens damages the cover slip, promptly report it to the teacher, professor, or any authorized personnel.

To prevent this from happening, exercise extra caution and adjust the high power objective lens slowly using the fine adjustment knob.

inna [3.1K]2 months ago

5 0

<span>First and foremost, ensure that the high power objective lens never comes into contact with or damages the coverslip. However, if the high power lens accidentally touches or cracks the coverslip,</span>

avoid utilizing the high power magnification. When using high power magnification, adjust only with the fine focus knob.

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A 450g mass on a spring is oscillating at 1.2Hz. The totalenergy of the oscillation is 0.51J. What is the amplitude.

Sav [3153]

Response:

A=0.199

Clarification:

We know that

Mass of spring=m=450 g= $=\frac{450}{1000}=0.45 kg$

Where 1 kg=1000 g

Frequency of oscillation=

$\nu=1.2Hz$

Energy for oscillation is 0.51 J

To determine the amplitude of oscillations.

Energy for oscillator= $E=\frac{1}{2}m\omega^2A^2$

Where $\omega=2\pi\nu$ =Angular frequency

A=Amplitude

$\pi=\frac{22}{7}$

Using the formula

$0.51=\frac{1}{2}\times 0.45(2\times \frac{22}{7}\times 1.2)^2A^2$

$A^2=\frac{2\times 0.51}{0.45\times (2\times \frac{22}{7}\times 1.2)^2}=0.0398$

$A=\sqrt{0.0398}=0.199$

Therefore, the amplitude of oscillation=A=0.199

4 0

25 days ago

A system expands from a volume of 1.00 l to 2.00 l against a constant external pressure of 1.00 atm. what is the work (w) done b

Keith_Richards [3271]

The amount of work performed by a system at consistent pressure is defined by the following equation:
$W=p \Delta V = p (V_f - V_i)$
where
p represents pressure
$V_f$ as the final volume
$V_i$ as the initial volume

Plugging the values given in this case into the formula gives us
$W=p (V_f -V_i)=(1.00 atm)(2.00 L-1.00 L)=1.00 L\cdot atm$

Considering that $1 atm \cdot L = 101.3 J$ , the result for the work done becomes
$W= 1.00 atm \cdot L = 101.3 J$

8 0

1 month ago

Read 2 more answers

A skateboarder is attempting to make a circular arc of radius r = 16 m in a parking lot. The total mass of the skateboard and sk

kicyunya [3294]

To address this question, we will utilize concepts linked to centripetal force, aligning it with the static frictional force acting on the object. Using this relationship, we can derive the velocity and input the known values. The defined values are:

$r = 16m$