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gizmo_the_mogwai
3 months ago
11

A child wants to pump up a bicycle tire so that its pressure is 1.2 × 105 pa above that of atmospheric pressure. if the child us

es a pump with a circular piston 0.035 m in diameter, what force must the child exert?
Physics
2 answers:
kicyunya [3.2K]3 months ago
7 0
The general formula is;
Pressure = Force/Area
Where,
Pressure = Required pressure + Atmospheric pressure = (1.2*10^5) + (101325) = 221325 Pa = 221325 N/m^2

Area = πD²/4 = π*0.035²/4 = 9.621*10^-4 m²

Thus,
Force, F = Pressure*Area = 221325*9.621*10^-4 = 212.94 N
Yuliya22 [3.3K]3 months ago
6 0

Answer:

The force required from the child amounts to 460.8 N.

Explanation:

We are given that pressure P=1.2\times 10^5pa

Radius of the circular piston r = 0.035 m

Thus, area A=\pi r^2=3.14\times 0.035^2=0.003846m^2

Next, we need to calculate the force achieved by the child.

We know force can be expressed as

Force=pressure\times area

Therefore, force will be represented as Force=1.2\times 10^5\times 0.00384=460.8N

So the force that the child must exert is 460.8 N.

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If an instalment plan quotes a monthly interest rate of 4%, the effective annual/yearly interest rate would be _____________. 4%
inna [3103]

Answer:

More than 48%

Explanation:

If the interest is calculated monthly based on the outstanding balance, it leads to an effective annual rate of...

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4 0
3 months ago
A very small round ball is located near a large solid sphere of uniform density. The force that the large sphere exerts on the b
Softa [3030]

Respuesta:

Opción e

Explicación:

La Ley de Gravitación Universal indica que toda masa puntual atrae a otra masa puntual en el universo con una fuerza que se dirige en línea recta entre los centros de masa de ambos, siendo esta fuerza proporcional a las masas de los objetos y inversamente proporcional a su separación. Esta fuerza atractiva siempre es dirigida del uno hacia el otro. La ley es aplicable a objetos de cualquier masa, sin importar su tamaño. Dos objetos grandes pueden ser considerados masas puntuales si la distancia entre ellos es considerablemente mayor que sus dimensiones o si presentan simetría esférica. En tales casos, la masa de cada objeto puede ser modelada como una masa puntual en su centro de masa.

La misma fuerza actúa sobre ambas bolas.

5 0
3 months ago
A supplier wants to make a profit by buying metal by weight at one altitude and selling it at the same price per pound weight at
Ostrovityanka [3204]

The appropriate choice is C.

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2 months ago
A conducting sphere 45 cm in diameter carries an excess of charge, and no other charges are present. You measure the potential o
Maru [3345]

Answer:

The excess charge is Q = 3.5 *10^{-7} \ C

Explanation:

According to the question, we are informed that

The diameter is d = 45 \ cm = 0.45 \ m

The potential of the surface is V = 14 \ kV = 14 *10^{3} \ V

The radius of the sphere is

r = \frac{d}{2}

by plugging in given values

r = \frac{0.45}{2}

r = 0.225 \ m

The potential at the surface is mathematically expressed as

V = \frac{k * Q }{r }

Where k is Coulomb's constant with a value k = 9*10^{9} \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.

Based on the question stating there are no other charges, Q represents the excess charge

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Q = \frac{V* r}{ k}

inserting the numerical values

Q = \frac{14 *10^{3} 0.225}{ 9*10^9}

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7 0
1 month ago
The young tree was bent and has been brought into a vertical position by the three guy cables. If tension at AB = 0, AC = 10 lb,
Keith_Richards [3271]

Answer:

The initially bent young tree has been straightened by adjusting the tensions of the three guy wires to AB = 7 lb, AC = 8 lb, and AD = 10 lb. Please calculate the force and moment reactions at the trunk's base point O, disregarding the weight of the tree.

C and D are situated 3.1' from the y-axis, while B and C are located 5.4' from the x-axis, and A has a height of 5.2'.

Explanation:

Refer to the attached image.

3 0
2 months ago
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