A child wants to pump up a bicycle tire so that its pressure is 1.2 × 105 pa above that of atmospheric pressure. if the child us

The peak wavelength for Betelgeuse is 828 nm

Explanation:

Wien's law describes how the surface temperature relates to a star’s peak wavelength:

where

represents the peak wavelength

T is the surface temperature

is Wien's constant

For Betelgeuse, the surface temperature is roughly

T = 3500 K

Consequently, its peak wavelength can be determined as:

Learn more about wavelength:

Response:

A=0.199

Clarification:

We know that  

Mass of spring=m=450 g=

Where 1 kg=1000 g

Frequency of oscillation=

Energy for oscillation is 0.51 J

To determine the amplitude of oscillations.

Energy for oscillator=

Where =Angular frequency

A=Amplitude

Using the formula

Therefore, the amplitude of oscillation=A=0.199

Answer:

a)n= 3.125 x electrones.

b)J= 1.515 x A/m²

c) =1.114 x m/s

d) ver explicación

Explanation:

La corriente 'I' = 5A =>5C/s

diámetro 'd'= 2.05 x m

radio 'r' = d/2 => 1.025 x m

número de electrones 'n'= 8.5 x

a) La cantidad de electrones que pasan por la bombilla cada segundo se determina mediante:

I= Q/t

Q= I x t => 5 x 1

Q= 5C

Como sabemos que: Q= ne

donde e es la carga del electrón, es decir, 1.6 x C

n= Q/e => 5/ 1.6 x

n= 3.125 x electrones.

b) La densidad de corriente 'J' en el cable se calcula como

J= I/A => I/πr²

J= 5 / (3.14 x (1.025x )²)

J= 1.515 x A/m²

c) La velocidad típica '' de un electrón se expresa como:

=

    =1.515 x / 8.5 x x |-1.6 x |

=1.114 x m/s

d) De acuerdo con estas ecuaciones,

J= I/A

= =

Si utilizaras un cable de doble diámetro, ¿cuáles de las respuestas anteriores cambiarían? ¿Aumentarían o disminuirían?

Arginine is classified as a basic amino acid since it has two amino groups alongside a single acid group. At a low pH level, all ionizable groups are protonated. As the pH rises slightly, the acid group loses its proton. When the pH increases further, one of the amino groups also loses a proton. At considerably high pH levels, none of the ionizable groups remain protonated.

Pkas

<span> <span><span> <span> pka1 = 1.82 </span> <span> pka2 = 8.99 </span> <span> pka3 = 12.48 </span> </span> </span></span> Thus, 9.20 is above the second pKa and below the third pKa. This indicates that the acid has already lost its proton, as has one of the amino groups, while the second amino group remains protonated. When an acid is not protonated, it carries a negative charge. An unprotonated amino group is neutral, whereas when protonated, the amino group bears a positive charge. Therefore, this amino acid exhibits one positive charge (from one of the amino groups) and one negative charge (from the acid), resulting in an overall neutral charge.

Answer:

D, C, B, A

Explanation:

The derivative from a velocity-time graph provides the acceleration value.

Segment A

Segment B

Segment C

Segment D

Sorted from the lowest to the highest acceleration:

D, C, B, A