Bernoulli's equation at a point on the streamline is
p/ρ + v²/(2g) = constant
where
p = pressure
v = velocity
ρ = air density, 0.075 lb/ft³ (under standard conditions)
g = 32 ft/s²
Point 1:
p₁ = 2.0 lb/in² = 2*144 = 288 lb/ft²
v₁ = 150 ft/s
Point 2 (stagnation):
The velocity at the stagnation point is zero.
The density stays constant.
Let p₂ denote the pressure at the stagnation location.
Then,
p₂ = ρ(p₁/ρ + v₁²/(2g))
p₂ = (288 lb/ft²) + [(0.075 lb/ft³)*(150 ft/s)²]/[2*(32 ft/s²)
= 314.37 lb/ft²
= 314.37/144 = 2.18 lb/in²
Thus, the answer is 2.2 psi
The astronaut's speed is described in the sentence. The astronaut moves at a rate of 10 meters each minute. To clarify: speed is defined as distance divided by time and is characterized solely by its magnitude, not its direction. Hence, the 10 meters per minute reflects this. We lack information about the astronaut's directional movement. In contrast to speed, velocity incorporates direction as well; for instance, a velocity of 10m/s due west provides a directional context. Consequently, without specified direction, the value indicated is merely speed.
Response:
2.5kN.m
Details:
Torque relates directly to the pitch diameter
= Ta/Tb= Da/Db
For 120/Tb= 0.25/0.5
This gives Tb= 2.469kN.m, roughly 2.5kN.m
The speed is V=27.24 m/s.
We need to utilize the linear momentum conservation principle:
The eagle's speed can be defined via two components:
Since speed is a scalar quantity.
Answer: t = 0.878s
Explanation: A note for you,
since the temperature decreases in a straight line, you can expect the movement speed to also behave linearly. However, this isn't exactly true (referring to the formula). Alternatively, utilize the interpolation principle: (x/v_surface + x/v_top)/2 = t.
While the answer may not match exactly, it should be a close approximation. You can use this formula, thus avoiding large distance calculations.
