Answer:
Given that the frog jumps every 10 seconds
(using digits from a random number table)
- It requires 7 jumps with 2 in the reverse direction (either left or right) for the frog to get off the board in 60 seconds.
- Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
- Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.
Step-by-step explanation:
A frog positioned right at the center of a 5ft long board is 2.5 ft away from either edge.
Every 10 seconds, the frog jumps left or right.
If the frog's jumps are LLRLRL, it will remain on the board at the leftmost square.
If it jumps as LLRLL, it will jump off the board after fifty seconds.
Given that the frog jumps every 10 seconds
(using digits from a random number table)
- It requires 7 jumps with 2 in reverse direction (either left or right) for the frog to get off the board in 60 seconds.
- Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
- Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.
James will retain his original t toy cars along with half of (t+13) cars, resulting in a total of...
... t + (t + 13/2) = (3t + 13)/2.... cars after receiving a gift from Paul.
The question seems to require answer choices, which are provided below:
a) sqrt(1 - x^2)
<span>b) x / sqrt(1 - x^2)</span>
<span>c) sqrt(1 - x^2) / x</span>
<span>d) 1 / sqrt(1 - x^2)
</span>
The correct selection is <span>c) sqrt(1 - x^2) / x</span>.
This is because cos u equals sqrt(1 - sin² u), which is sqrt(1 - x²), and cot u is defined as cos u divided by sin u.
Answer: The other two observations are 97 and 107.
Explanation:
We know that
Mean = 100
Mode = 98
Range = 10
And from the formula,
Range = Highest - Lowest.
Let’s set the highest observation as x and the lowest as y.
Thus, we have the equation x - y = 10 (equation 1).
The observations can be represented as:
x, 98, 98, y.
Using the mean formula yields:
Mean = 
.
This means our second equation is:
x + y = 204.
By applying the elimination method to solve these linear equations, we find:
x = 97.
and
.
Therefore, the other two observations are 97 and 107.
