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jenyasd209
3 months ago
14

When drawing the Lewis structure for a molecule, after drawing the skeletal structure and distributing all of the electrons arou

nd the the terminal atoms, what actions should be taken if the central atom does not have a complete octet
Chemistry
1 answer:
Anarel [2.9K]3 months ago
7 0

Answer: Rearrange the lone pairs of electrons from the outer atom(s) to create double or triple bonds with the central atom.

Explanation:

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Bleach contains the active ingredient NaClO. Analysis of bleach involves two sequential redox reactions: First, bleach is reacte
VMariaS [2998]

Answer:

0.31%

Explanation:

For the chemical reaction:

I₂ + 2 S₂O₃²⁻ → 2 I⁻ + S₄O₆²⁻

0.043 L multiplied by 0.117 M of sodium thiosulfate gives 5.031x10⁻³ moles of S₂O₃²⁻

5.031x10⁻³ moles of S₂O₃²⁻ produces:

ClO⁻⁻ + 2 H⁺ + 2 I⁻ → I₂ + Cl⁻ + H2O

2.5156x10⁻³ moles of I₂ equates to moles of NaClO

2.5156x10⁻³ moles of NaClO times \frac{74,44 g}{1mol} yields 0.187 g of NaClO

Thus, the mass percentage composition is:

\frac{0,187 g of NaClO}{60 g Of Bleach} x 100 = 0.31%

I hope this helps!

5 0
3 months ago
Determine the type of each chemical equation describing a precipitation reaction. C a 2 + ( a q ) + S O 4 2 − ( a q ) ⟶ C a S O
lorasvet [2795]

Answer:

C a B r 2 ( a q ) + N a 2 S O 4 ( a q ) ⟶ 2 N a B r ( a q ) + C a S O 4 ( s )

Explanation:

A precipitation reaction involves a displacement process where a solid precipitate forms. This precipitate, being solid, is distinct from the other products and can be separated.

C a 2 + ( a q ) + S O 4 2 − ( a q ) ⟶ C a S O 4 ( s )

This equation is incorrect as it results in only C a S O 4.

C a B r 2 ( a q ) + N a 2 S O 4 ( a q ) ⟶ 2 N a B r ( a q ) + C a S O 4 ( s )

This is the proper reaction where C a S O 4 precipitate is produced.

C a 2 + ( a q ) + 2 B r − ( a q ) + 2 N a + ( a q ) + S O 4 2 − ( a q ) ⟶ 2 N a + ( a q ) + 2 B r − ( a q ) + C a S O 4 ( s )

This equation illustrates the ionic details of the precipitation reaction.

8 0
3 months ago
A 25.0-g sample of ice at -6.5oC is removed from the freezer and allowed to warm until it melts. Given the data below, select al
KiRa [2933]

Answer:

B, D

Explanation:

We need to recognize that the ice will rise in temperature from -6.5 ºC to 0 ºC for it to change into water.

Let's define q₁ as the heat needed to warm the ice to 0ºC, and q₂ as the heat for the transition from solid to liquid.

The calculation for q₁ is as follows:

q₁ = s x m x ΔT, where s represents the specific heat of ice (2.09 J/gºC), m is the mass, and ΔT is the temperature difference.

For q₂, the enthalpy of fusion is computed as:

q₂ = C x ΔT

with C indicating the specific heat for the phase transition, denoted as AH in kJ/mol.

All necessary data for computing q₁, q₂, and the total heat change (q₁ + q₂) is provided.

q₁ = 25.0 g x (2.09 J/gºC) x (0 - (-6.5 ºC))

q₁ = 339.6 J = 0.339 kJ

q₂ = (25 g/18 g/mol) x 6.02 kJ/mol = 1.39 x 6.02 kJ = 8.36 kJ

Combining these values gives us qtotal = 0.339 kJ + 8.36 kJ = 8.70 kJ.

Now we can answer the question:

(a) False, AH refers to the heat capacity during melting.

(b) True, as we concluded earlier.

(c) False, there’s only one phase transition from solid (ice) to liquid.

(d) True based on our calculations above.

(e) False, according to our findings.

7 0
3 months ago
The following data were obtained for a complex of nickel at 575 nm in a 1.00 cm cell. Using Microsoft Excel or some other graphi
castortr0y [3046]
Please refer to the attached explanation below. It is widely acknowledged that variations in the complex formulations of metals significantly affect the conduction properties of molecular materials, which demonstrate unusual magnetic characteristics and conductivity, relevant to fields such as material chemistry, supramolecular studies, and biochemistry. The electrochemical behavior of nickel (Ni(II)) complexes was examined using techniques like cyclic voltammetry (CV), rotating coulometry, and disc electrode (RDE).
7 0
2 months ago
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