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Zarrin
21 day ago
11

In this lab, you will do experiments to identify types of changes. Using the question format you learned (shown above), write an

investigative question that you can answer by doing these experiments.
Chemistry
1 answer:
VMariaS [2.6K]21 day ago
4 0

Response:

How can you differentiate a physical change from a chemical change?

Clarification:

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The next 3 questions will walk you through using the Henderson-Hasselbalch equation for the following question. For each step pr
lions [2633]

Response:

The pKa value is 13.0.

Clarification:

pKa + pKb = 14

For trimethylamine, Kb = 6.3 × 10^{-5}

Calculating pKb: pKb = - log (6.3 × 10^{-5})

= 1.0

Thus, pKa = 14 - pKb = 14 - 1.0

pKa = 13.0

Verification: The typical range for pKa in weak acids is from 2 to 13.

8 0
1 month ago
A stock solution of Cu2+(aq) was prepared by placing 0.8875 g of solid Cu(NO3)2∙2.5 H2O in a 100.0-mL volumetric flask and dilut
Anarel [2593]

Answer:

3.816 × 10⁻³ M

Explanation:

A stock solution of Cu²⁺(aq) is made by dissolving 0.8875 g of solid Cu(NO₃)₂∙2.5H₂O in a 100.0-mL volumetric flask, and then brought up to volume with water. What is the molarity (in M) of Cu²⁺(aq) in this stock solution?

We can derive the following relations:

  • The molar mass of Cu(NO₃)₂∙2.5H₂O is 232.59 g/mol.
  • Each mole of Cu(NO₃)₂∙2.5H₂O yields one mole of Cu²⁺.

The moles of Cu²⁺ present in 0.8875 g of Cu(NO₃)₂∙2.5H₂O are:

0.8875gCu(NO_{3})_{2}.2.5H_{2}O\times \frac{1molCu(NO_{3})_{2}.2.5H_{2}O}{232.59gCu(NO_{3})_{2}.2.5H_{2}O} \times \frac{1molCu^{2+} }{1molCu(NO_{3})_{2}.2.5H_{2}O} =3.816\times10^{-3} molCu^{2+}

The molarity of Cu²⁺ is:

\frac{3.816\times10^{-3} mol}{100.0 \times10^{-3}L} =3.816\times10^{-2}M

4 0
20 days ago
What is the mass percent of a solution of 7.6 grams sucrose in 83.4 grams of water
Tems11 [2387]

Response:

The mass percentage of a solution comprising 7.6 grams of sucrose and 83.4 grams of water equals 8.351 %.

Details:

Provided data:

Sucrose mass = 7.6 grams

Water mass = 83.4 grams

In this scenario, sucrose acts as the solute, while water is the solvent.

The calculation for mass percent of a solution is done using the following formula:

Mass percent = (Mass of Solute/Mass of Solution)(100)

As sucrose is the solute, the mass equals 7.6 grams.

The total mass of the solution, which includes both sucrose and water, comes out to:

Total mass = 7.6 grams + 83.4 grams = 91 grams

Therefore, applying the values gives mass percent = (7.6/91)(100) = 8.351 %.

7 0
1 month ago
Oxygen at 150 k and 41.64 atm has a tabulated specific volume of 4.684 cm3/g and a specific internal energy of 1706 j/mol. calcu
lions [2633]

Specific enthalpy is defined as the overall energy in a system attributed to its temperature and pressure, measured per unit mass. It is essential in thermodynamic calculations when one needs to determine the energy for a specific unit mass of a component.

Specific enthalpy can be computed with the equation:

H = U + PV

For this example, the specific volume is 4.684 cm³/g or 149.888 cm³/g moles, which translates to 149.888 × 10⁻³ J/g moles.

The specific internal energy (U) is 1706 J/mol, and the pressure measured is 41.64.

Calculating gives us H = 1706 + 41.64 × 149.888 × 10⁻³ × 101.3 joules

= 2428 joules / mole


5 0
19 days ago
A Venn diagram is used to compare and contrast different topics. The items that are unique to each topic are represented in the
VMariaS [2667]

Answer:

Endothermic: water formation from ice and a cold instant ice pack  Explanation:

8 0
1 month ago
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