The Chemistry Regents is one of the four science Regents exams. The remaining three are Earth Science, Living Environment, and Physics. Passing at least one of these four exams is a requirement for high school graduation.
The percentage of calcium carbonate that reacted is 2.5%. The reaction in question allows us to determine the equilibrium Kp: Kp = the partial pressure of carbon dioxide, since the other components are solids. We'll apply the ICE table to the provided equilibrium. At the start, we have 0.2 for calcium carbonate with no initial moles of other substances. As the reaction progresses, we set the changes to be -x for calcium carbonate, +x for carbon dioxide, and +x for the other product, leading us to an equilibrium of 0.2-x for calcium carbonate while both other products are at x. Using Kp = Kc(RT)ⁿ, where n represents the mole difference of gaseous products and reactants, we find n to equal 1 for this reaction. With R as the gas constant (8.314 J/mol K) and the temperature at 800 °C (1073 K), we substitute the values accordingly. Upon calculation, we find x = 0.005, which indicates the amount of calcium carbonate that dissociated or reacted, leading us to the reacted percentage.
Answer: Yes, there is sufficient sodium carbonate available.
Explanation:
In this scenario, according to the specified reaction:
Using stoichiometry, one can figure out the grams of sodium carbonate required to neutralize 1,665 g of sulfuric acid as outlined below:
Hence, the amount on hand is 2.0 kg, which leaves 0.2 kg as surplus, therefore:
A. Yes, there is sufficient sodium carbonate available.
Best regards.
1) The chemical equation is
Cu + 2AgNO3 ---> Cu (NO3)2 + 2Ag
2) Molar ratios are as follows:
1 mol Cu: 2 moles AgNO3: 1 mol Cu (NO3)2: 2 mol Ag
3) Converting 12.83 * 10^23 atoms of Cu to moles gives:
12.83 * 10^23 atoms / (6.02 * 10^23 atoms / mol) = 2.131 mol Cu
4) Using the ratios:
2.131 mol Cu * 2 mol Ag / 1 mol Cu = 4.262 mol Ag
5) To convert 4.262 mol of silver to grams, use the atomic weight of silver:
mass = moles × atomic mass = 4.262 mol * 107.9 g / mol = 459.9 grams
Answer: 459.9 g
