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Grace
1 month ago
11

A car rolls down a ramp in a parking garage. The horizontal position of the car in meters over time is shown below. Graph of ver

tical position (in meters) on y axis and time (in seconds) on x axis. The initial position is 12 m at t=0 s, and the position decreases linearly to 6 m at t=8 s. Then the position is constant at 6 m until t=16 s, then decreases linearly to 0 m at t=24 s. Graph of vertical position (in meters) on y axis and time (in seconds) on x axis. The initial position is 12 m at t=0 s, and the position decreases linearly to 6 m at t=8 s. Then the position is constant at 6 m until t=16 s, then decreases linearly to 0 m at t=24 s. What is the displacement of the car between 0\text{ s}0 s0, start text, space, s, end text and 24\text{ s}24 s24, start text, space, s, end text? 6 \text mmstart text, m, end text What is the distance traveled by the car between 0\text{ s}0 s0, start text, space, s, end text and 24\text{ s}24 s24, start text, space, s, end text?

Physics
1 answer:
Ostrovityanka [3.2K]1 month ago
3 0

Answer:

d_total = 12 m

Explanation:

In this kinematics scenario illustrated in the graph provided, we determine the distance traveled over a 24-second duration.

The comprehensive distance can be calculated as follows:

d_total = d₁ + d₂ + d₃

Given that d₂ on the graph is level (v=0), its distance equates to zero, hence d₂ = 0.

The distance for d₁ is calculated as:

d₁ = 12 - 6 = 6 m

For distance d₃:

d₃ = 6 - 0 = 6 m

Thus, the overall distance covered is:

d_total = 6 + 0 + 6

d_total = 12 m

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An airplane pilot wishes to fly directly westward. According to the weather bureau, a wind of 75.0 km/hour is blowing southward.
Softa [3030]

Answer:

The plane's speed in relation to the ground is 300.79 km/h.

Explanation:

Provided details include:

Wind speed = 75.0 km/hr

Plane's airspeed = 310 km/hr

Next, we must find the ground speed of the plane

Calculating the angle

Using the angle formula

\sin\theta=\dfrac{v'}{v}

Where v' represents the wind speed

v represents the plane's speed

We will substitute the values into the formula

\sin\theta=\dfrac{75}{310}

\theta=\sin^{-1}(\dfrac{75}{310})

\theta=14.0^{\circ}

Now, we must find the resultant speed

Using the resultant speed formula

\cos\theta=\dfrac{v''}{v}

Insert the values into the formula

\cos14=\dfrac{v''}{310}

v''=\cos14\times310

v''=300.79\ km/h

Consequently, the plane's speed in relation to the ground equals 300.79 km/h.

6 0
1 month ago
A graph of the net force F exerted on an object as a function of x position is shown for the object of mass M as it travels a ho
Softa [3030]

The alteration in kinetic energy is \Delta K = 3Fd

Clarification:

According to the work-energy principle, the task performed on an object corresponds to the alteration in its kinetic energy. In mathematical terms:

W=K_f -K_i= \Delta K

where:

W signifies the work performed on the object

K_f denotes the kinetic energy at the end

K_i indicates the kinetic energy at the start

Furthermore, when the force is exerted in line with the object’s motion, the work done is expressed as:

W=F\Delta x

Here,

F represents the force’s magnitude

\Delta x denotes the object’s displacement

In this scenario, the force impacting the object is

F

While the distance moved is the horizontal length traveled, hence

\Delta x = 3d

Consequently, the work accomplished is

W=(F)(3d)=3Fd

Thus, the alteration in kinetic energy amounts to

\Delta K = 3Fd

Learn more about work and kinetic energy:

5 0
1 month ago
When a charge is placed on a metal sphere, it ends up in equilibrium at the outer surface. Use this information to determine the
Maru [3345]

Answer:

a

The value at a point inside is Zero

b

The electric field is E = 2.7*10^{6} \ N/C

Explanation:

We know from the problem that

The charge magnitude is q = 3.0 \mu C = 3.0 *10^{-6} \ C

The radius of the spherical ball is r = 5.0 \ mm = 0.005 \ m

According to Gauss’s law, the enclosed charge within a conductor is zero which indicates that the electric field within the spherical ball is zero

On the outside, the electric field around the spherical ball is mathematically expressed as

E = \frac{kq}{ a^2}

Here a denotes a point outside the spherical ball with its value of a = 10 \ cm = \frac{10}{100} = 0.1 \ m

and k represents Coulomb's constant, valued at

k = 9*10^{9}\ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.

=> E = \frac{ 3 *10^{-6} * 9*10^9 }{ (0.1)^2}

=> E = 2.7*10^{6} \ N/C

5 0
12 days ago
A 5-kg concrete block is lowered with a downward acceleration of 2.8 m/s2 by means of a rope. The force of the block on the Eart
Maru [3345]

The moment the body impacts the ground, two types of Forces are produced: the gravitational pull and the Normal Force. This aligns with Newton's third law, indicating that every action has an equal and opposite reaction. If the downward force of gravity is directed toward the earth, the reactionary force from the block acts upwards, equivalent to its weight:

F = mg

Where,

m = mass

g = gravitational acceleration

F = 5*9.8

F = 49N

Consequently, the answer is E.

5 0
1 month ago
If a 50.0-kg mass weighs 554 n on the planet saturn, calculate saturn’s radius
ValentinkaMS [3465]

Answer:

17.35 × 10^(-6) m

Explanation:

Mass; m = 50 kg

Weight; W = 554 N

From the formula:

W = mg

This simplifies to; 554 = 50g

g = 554/50

g = 11.08 m/s²

Also, using the formula;

mg = GMm/r²

hence; g = GM/r²

Rearranging gives;

r = √(GM/g)

With G as a known constant of 6.67 × 10^(-11) Nm²/kg²

r = √(6.67 × 10^(-11) × 50/11.08)

r = 17.35 × 10^(-6) m

8 0
1 month ago
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