9 days ago

A single slit of width 0.3 mm is illuminated by a mercury light of wavelength 254 nm. Find the intensity at an 11° angle to the

axis in terms of the intensity of the central maximum.

Physics

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The acceleration of segment D is m/s2. Rank segments A, B , C from least accelerations to greatest acceleration. Least

Ostrovityanka [3204]

Answer:

D, C, B, A

Explanation:

The derivative from a velocity-time graph provides the acceleration value.

Segment A

$\frac{dy}{dx} = \frac{15m/s}{1s} = 15m/s^2$

Segment B

$\frac{dy}{dx} = \frac{5m/s}{1s} = 5m/s^2$

Segment C

$\frac{dy}{dx} = \frac{0m/s}{2s} = 0m/s^2$

Segment D

$\frac{dy}{dx} = \frac{-20m/s}{1s} = -20m/s^2$

Sorted from the lowest to the highest acceleration:

D, C, B, A

8 0

2 months ago

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A rocket in deep space has an exhaust-gas speed of 2000 m/s. When the rocket is fully loaded, the mass of the fuel is five times

Sav [3153]

Answer:

$v_{f}$ = 1,386 m / s

Explanation:

The mechanism behind rocket propulsion is defined by the formula

$v_{f}$ - v₀ = $v_{r}$ ln (M₀ / Mf)

Here, v refers to the initial, final, and relative velocities, while M indicates the masses

The provided values include the relative velocity (see = 2000 m / s) and the initial mass, where the mass of the rocket when loaded is represented as (M₀ = 5Mf)

For our analysis, we assume the rocket begins at rest (v₀ = 0)

Once half of the fuel has burnt, the mass ratio indicates that the current mass is

M = 2.5 Mf

$v_{f}$ - 0 = 2000 ln (5Mf / 2.5 Mf) = 2000 ln 2

$v_{f}$ = 1,386 m / s

3 0

2 months ago