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Vikki
1 month ago
7

A kinesin that is transporting a secretory vesicle uses approximately 80 ATP molecules/s. Each ATP provides a kinesin molecule w

ith an energy of about 0.8 × 10-19 J. If the velocity of the kinesin is 800 nm/s, can you determine the force the kinesin is exerting, if you assume that all the ATP energy is used (100% efficiency)? If you can, find it and give your answer in newtons. If not, answer with 0.
Physics
1 answer:
inna [3.1K]1 month ago
7 0

Answer:

The force is  F = 8*10^{-12} \ N

Explanation:

According to the inquiry, we understand that

     The rate at which ATP molecules are utilized is R = 80 ATP/ s

       The energy yielded by a single ATP molecule is  E_{ATP} = 0.8 * 10^{-19} J

       The kinesin's velocity is  v = 800 nm/s = 800*10^{-9} m/s

The power generated by the ATP in one second can be expressed mathematically as

       P = E_{ATP} * R

After substituting the values

       P = 80 * 0.8*10^{-19 }

       P = 6.4 *10^{-18}J/s

Now this power can be represented mathematically as

       P = F * v

Where  F indicates the force exerted by the kinesin

Therefore

          F = \frac{P}{v}

after substituting input values

            F = \frac{6.4*0^{-18}}{800 *10^{-9}}

           F = 8*10^{-12} \ N

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1 month ago
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Answer:

After a duration of 2.0 seconds, the angular momentum of the system is L= 2(4A+3B+2C+D)x.

Explanation:

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\tau_d = Dx.

This leads to a total torque on the stick as

\tau_{tot} =\tau_a+\tau_b+\tau_c+\tau_d

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Subsequently, this torque results in an angular acceleration \alpha in accordance with the formula

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\alpha = \dfrac{\tau_{tot} }{I}

\alpha =\dfrac{x(4A+3B+2C+D)}{\dfrac{1}{3}m(4x)^2 }

\boxed{\alpha =\dfrac{3(4A+3B+2C+D)}{16mx } .}.

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L = I\omega,

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Given \omega = \alpha t, we conclude that

$L = \dfrac{1}{3}m (4x)^2  *\dfrac{3(4A+3B+2C+D)}{16mx }* t$

L= (4A+3B+2C+D)x t

Thus, t = 2.0s, the angular momentum is

\boxed{ L= 2(4A+3B+2C+D)x. }

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