Refer to the diagram below.
This discussion operates under a basic analysis that overlooks air resistance and variations in the terrain the missile traverses.
Let V₀ be the launch velocity, at an angle θ to the horizontal.
The horizontal velocity component equals V₀ cosθ.
If the flight duration is
, then
where r represents the missile's range.
The time t at which the missile is at ground level is expressed by
where g signifies acceleration due to gravity.
t = 0 signifies the missile's launch. Thus
Consequently,
Typically, an angle of θ=45° is optimal for achieving maximum range, resulting in
This discussion applies more accurately to a scud missile than to a powered, guided missile.
Response:
Usually, θ=45°
Answer:
The force will rise in direct relation to the mass of the objects
Explanation:
The gravitational acceleration remains constant. It is measured in meters per second squared or m/s². The average value is 9.81 m/s², calculated from observations made on varying surfaces. In reality, the acceleration can vary based on the geographical shape of the Earth relative to the earth's magnetic field and gravitational force.
For instance, if a single washer weighs 20 kg, with the gravity at 9.81 m/s², the weight would be:
F = ma
= 
If there are three washers, the total weight calculates as:
F = 3 * 20 * 9.81
= 588.6 N
Answer:
267.07 km
Explanation:
The given earth's radius is 6378.1 km
In the year 2014, the magnetic north pole was situated 2.40° away from the geographical north pole
2.40°
The linear distance can be calculated using the formula 
Thus, travelling from the magnetic north pole to the geographic north pole requires a distance of 267.07 km
The static frictional force exceeds the kinetic frictional force, indicating that the static frictional force is over 1200 N. Explanation: The frictional force opposes the motion of any object on a surface, caused by interactions between the surface molecules and the object. It is known that static friction is typically stronger than kinetic friction (this is the reason initiating motion requires more force than keeping it moving along a surface). Hence, option 3 correctly describes the situation.
A. A car moving at a constant speed on a flat, straight road. B. A vehicle traveling at a steady speed on a 10-degree incline. An object operates within an inertial reference frame if there is no net force acting upon it. According to Newton's second law, this implies that the object's acceleration also equals zero. Assessing the scenarios yields: A. A car moving at a constant speed on a flat road qualifies as an inertial reference frame, since its velocity and direction remain unchanged; thus, acceleration is zero. B. A car moving steadily up a 10-degree incline still constitutes an inertial reference frame, for similar reasons. C. A car accelerating after departing a stop sign does not represent an inertial frame due to its change in speed. D. A car driving at a steady speed around a curve cannot be considered an inertial reference frame since its direction is changing, resulting in a change in velocity and thus acceleration. Therefore, options A and B are correct.
