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vivado
1 month ago
12

A girl pushes an 18.15 kg wagon with a force of 3.63 N. what is the acceleration?

Physics
2 answers:
Keith_Richards [3.2K]1 month ago
5 0
The acceleration is 0.2 m/s², determined by dividing the force by the mass, calculated as follows: Acceleration = 3.63 ÷ 18.15 results in 0.2 m/s².
ValentinkaMS [3.4K]1 month ago
3 0
To calculate acceleration, divide the force by mass: F = m × a results in 3.63 = 18.15 × a leading to 3.63 = 18.15a, which gives a = 3.63/18.15, equating to a = 0.2 m/s².
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Describe a well-known hypothesis that was discarded because it was found to be untrue.earth-centered model of the universe. the
inna [3103]
The previously accepted theory that was proven incorrect is the Geocentric Theory, which placed Earth at the center of the universe. This idea was introduced by philosopher Ptolemy. He formulated this hypothesis based on his observations that celestial bodies such as the Sun, stars, and the moon appeared to move around Earth from our vantage point. However, Galileo Galilei contradicted this notion with his Heliocentric Theory. He used a telescope to observe that Venus undergoes phases, akin to the moon, leading him to conclude that the alignment of Venus, Earth, Moon, and Sun did not support the earlier theory. 
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2 months ago
During a snowball fight two balls with masses of 0.4 and 0.6 kg, respectively, are thrown in such a manner that they meet head-o
Yuliya22 [3333]

Answer:

The snowball's speed after the impact is 3 m/s

Explanation:

Given the following:

mass of each ball

m₁ = 0.4 Kg

m₂ = 0.6 Kg

initial speed of both balls = v₁ = 15 m/s

Speed of 1 Kg mass post-collision =?

Applying conservation of momentum

m₁ v₁ - m₂ v₁ = (m₁+m₂) V

A negative velocity indicates that the second ball moves in the opposite direction.

0.4 x 15 - 0.6 x 15 = (1) V

Therefore,

V = - 3 m/s

Consequently,

The snowball's speed following the collision is 3 m/s

8 0
2 months ago
The magnitude of the Poynting vector of a planar electromagnetic wave has an average value of 0.939 W/m2. The wave is incident u
Yuliya22 [3333]

Answer:

The total energy can be expressed as T = 169.02 \ J

Explanation:

The problem states that

The Poynting vector, which measures energy flux, equals k = 0.939 \ W/m^2

The rectangle's length is represented by l = 1.5 \ m

The width of the rectangle is w = 2.0 \ m

The duration considered is t = 1 \ minute = 60 \ s

Mathematically, the overall electromagnetic energy incident on the area is given by

T = k * A * t

where A denotes the area of the rectangle, calculated as

A= l * w

By plugging in the respective values

A= 2 * 1.5

A= 3 \ m^2

Again substituting values

T = 0.939 * 3 * 60

T = 169.02 \ J

5 0
2 months ago
A simple harmonic wave of wavelength 18.7 cm and amplitude 2.34 cm is propagating along a string in the negative x-direction at
Ostrovityanka [3204]

Answer

Given:

Wavelength = λ = 18.7 cm

                  = 0.187 m

Amplitude, A = 2.34 cm

Velocity, v = 0.38 m/s

A)  Calculate the angular frequency.

     f = \dfrac{v}{\lambda}

     f = \dfrac{0.38}{0.187}

     f =2.03\ Hz

Angular frequency,

ω = 2π f

ω = 2π x 2.03

ω = 12.75 rad/s

B) Calculate the wave number:

      K = \dfrac{2\pi}{\lambda}

     K= \dfrac{2\pi}{0.187}

    K =33.59\ m^{-1}

C)

Since the wave is traveling in the -x direction, the sign is positive between x and t

y (x, t) = A sin(k x - ω t)

y (x, t) = 2.34 sin(33.59 x - 12.75 t)

4 0
3 months ago
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Ostrovityanka [3204]

Answer:

Explanation:

According to the parameters provided,

mass of the clay lump, m₁ = 0.05 kg

initial velocity of the lump, u₁ = 12 m/s

mass of the cart, m₂ = 0.15 kg

initial speed of the cart, u₂ = 0

As the clay adheres to the cart, we have an inelastic collision scenario. Let v represent the combined speed of both the cart and lump post-collision. Given that momentum is conserved, we have:

m_1u_1+m_2u_2=(m_1+m_2)v

v=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

v=\dfrac{0.05\ kg\times 12\ m/s+0}{0.05\ kg+0.15\ kg}

The resultant speed is v = 3 m/s.

Thus, the final speed of both cart and lump following the collision is 3 m/s. This concludes the solution.

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