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3 months ago

Which graph represents the motion of an object traveling with a positive velocity and a negative acceleration?

Physics

2 answers:

Keith_Richards [3.2K]3 months ago

6 0

I think the right choice according to the illustration above is the second option. The graph demonstrating the motion of an object moving with a positive velocity and a negative acceleration is graph 2, which shows a curve that increases in y as x rises. I hope this resolves the question.

Yuliya22 [3.3K]3 months ago

5 0

Answer
graph 2

Explanation
Velocity refers to the speed at which displacement changes.
Velocity = (change in displacement)/(change in time)
In graph 2, the slope of the curve is positive, indicating a positive velocity.
Acceleration indicates how velocity varies.
The incline of the same curve (graph 2) is diminishing. This suggests that the velocity is falling, signifying negative acceleration.

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James Cameron piloted a submersible craft to the bottom of the Challenger Deep, the deepest point on the ocean's floor, 11,000 m

serg [3582]

Answer:

$4.1\cdot 10^8 N$

Explanation:

To begin with, we must determine the pressure acting on the sphere, which is calculated using:

$p=p_0 + \rho g h$

where

$p_0 =1.01\cdot 10^5 Pa$ denotes the atmospheric pressure

$\rho = 1000 kg/m^3$ represents the density of the water

$g=9.8 m/s^2$ signifies the acceleration due to gravity

$h=11,000 m$ indicates the depth

By substituting these values,

$p=1.01\cdot 10^5 Pa + (1000 kg/m^3)(9.8 m/s^2)(11,000 m)=1.08\cdot 10^8 Pa$

The sphere's radius is calculated as r = d/2 = 1.1 m/2 = 0.55 m

Thus, the sphere's total surface area can be expressed as

$A=4 \pi r^2 = 4 \pi (0.55 m)^2=3.8 m^2$

Consequently, the inward force acting on the sphere equals

$F=pA=(1.08\cdot 10^8 Pa)(3.8 m^2)=4.1\cdot 10^8 N$

8 0

3 months ago

Read 2 more answers

Steel blocks A and B, which have equal masses, are at TA = 300 oC and T8 = 400 oC. Block C, with mc - 2mA, is at TC = 350 oC. Bl

serg [3582]

Answer:

b) TA = TB = TC

Explanation:

When the blocks are brought into contact and isolated from the environment, they will exchange heat until they achieve thermal equilibrium.
During this exchange, the hotter body will lose heat, which will be gained by the cooler body.
The equilibrium state will be established once this equation is satisfied:

$\Delta Q = c_{st}* m_{A} * (T_{fin} - T_{0A} ) = c_{st}* m_{B} * (T_{0B} - T_{fin} )$

Substituting the initial temperatures T₀A = 300º C and T₀B = 400ºC, while simplifying for equal block masses mA = mB, enables us to solve for the final temperature, Tfin:

$(400 \ºC - T_{fin}) = (T_{fin} - 300 \ºC) \\ \\ 2* T_{fin} = 700\ºC\\ \\ T_{fin} = 350\ºC$

At equilibrium, when both blocks combine, they will yield a uniform final temperature of 350ºC.
When block C, also at this temperature, makes contact, all three blocks will simultaneously reflect this final temperature of 350 ºC.
Therefore, option b) is correct.

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3 months ago