The second question necessitates a figure to provide an answer. For the initial question
The acceleration of the sack is
1.5² - 0² = 2a(0.2)
a = 5.63 m/s²
The ramp's reaction force is
F = 8 kg (5.63 m/s²)
F = 45 N
Differentiate the kinematic equation with respect to time to find the velocity's rate of increase.
Answer:
1.05 N
Explanation:
K = 0.7 N/m
e = 1.5 m
F =?
According to Hooke's law:
F = Ke
= 0.7×1.5
= 1.05 N
To start, we first need to determine the kinetic energy of the penny before it strikes the ground. This is calculated using the formula where m equals 5.25 g, which is 0.00525 kg for the penny's mass, and v equals 3.27 m/s for its speed. Replacing the values into the equation provides: When the penny lands, all this kinetic energy transforms into internal energy for both the penny and the ground. If half of this energy goes into the penny's internal energy, the change is determined by a specific formula where m is the penny's mass, Cs is its specific heat capacity (2.03 J/gC), and

, the change in temperature. To find the last element, the equation will be solved.