Derive an expression for the acceleration of the car. Express your answer in terms of D and vt Determine the time at which the s
1 answer:
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Response:
Once it has crossed, the locomotive requires 17.6 seconds to achieve a speed of 32 m/s.
Details:
The locomotive's acceleration is 1.6
The duration taken to pass the crossing is 2.4 seconds.
We can apply the motion equation, v = u + at, where v represents final velocity, u indicates initial velocity, a denotes acceleration, and t signifies time.
When the speed reaches 32 m/s, we have v = 32 m/s, u = 0 m/s, and a= 1.6 .
32 = 0 + 1.6 * t
t = 20 seconds.
Therefore, the locomotive attains a speed of 32 m/s after 20 seconds, and it passes the crossing in 2.4 seconds.
Thus, after clearing the crossing, it takes an additional 17.6 seconds to reach the speed of 32 m/s.
Answer:
The typical weight of a human heart is approximately 0.93 lbs.
Explanation:
Based on this,
the heart's weight constitutes about 0.5% of total body mass.
Total human weight = 185 lbs
Let the entire body weight be represented as w and the heart's weight as .
We aim to determine the heart's weight for a human
Using the provided information
Where, h = heart weight
w = human weight
The final weight of a human heart is 0.93 lbs.
Response: The spring constant is 25 N/m.
Details:
The body’s mass is 25 g, which converts to 0.025 kg (since 1 kg = 1000 g).
The total oscillations are 20 in 4 seconds.
Oscillations per second =
Spring's frequency of vibration is =
The spring constant 'k' can be derived from the relationship involving frequency, mass, and spring constant.
The spring constant is 25 N/m.