Answer:
σ₁ =
C/m²
σ₂ =
C/m²
Explanation:
Provided Information:
i) Smaller sphere's radius ( r ) = 5 cm.
ii) Larger sphere's radius ( R ) = 12 cm.
iii) Electric field at the larger sphere's surface ( E₁ ) = 358 kV/m, which is equivalent to 358 * 1000 v/m


Charge (Q₁) = 572.8
C
Since the electric field inside a conductor is zero, the electric potential ( V ) remains constant.
V = constant
∴

=
C
Surface charge density ( σ₁ ) for the larger sphere.
Calculated Area ( A₁ ) = 4 * π * R² = 4 * 3.14 * 0.12 = 0.180864 m².
σ₁ =
=
=
C/m².
Surface charge density ( σ₂ ) for the smaller sphere.
Calculated Area ( A₂ ) = 4 * π * r² = 4 * 3.14 * 0.05² = 0.0314 m².
σ₂ =
=
=
C/m²
Conclusion:
The total net force acting on the objects is 16 N, directed towards the right.
Clarification:
It is stated that,
The force exerted by the dog,
(to the right)
The force exerted by Simone,
(backward)
Here, assume the backward direction is negative and the right direction is positive.
The net force will move in the direction where the larger force is present. The net force can be calculated as:


F = 16 N
Thus, the net force amounts to 16 N, acting towards the right.
The derived frequency equals 2.63 Hz. Explanation: For an object weighing 8.0 kg with a spring stretching 3.6 cm, calculations involving the spring constant and oscillation frequency lead to this specific oscillation rate.