Two parallel wires carry a current I in the same direction. Midway between these wires is a third wire, also parallel to the oth
er two, which carries a current 0.5 I, but in the direction opposite from the first two wires. Two more wires with 0.5 I, in the same direct as the third wire, are placed the same distance as the third wire but on either side of the first two wires. In which direction are the net forces on the outer wires?
2 answers:
Answer:
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Initially, I create a diagram illustrating the scenario. I considered the attractive force as positive and the repulsive force as negative. Afterward, I calculate the net force acting on the outer left wire caused by the other wires; the result is negative, indicating the presence of a repulsive force. Thus, the force is directed away from the wire, as depicted in the diagram.
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Where G represents the gravitational constant and M denotes the mass of the planet.
Now, let’s compute the time value.
Ultimately, the time for the rock to hit the surface is t = 87.58s.