The intensity of the sound increases because sound waves are mechanical waves, meaning they cannot move through a vacuum and require a medium to propagate.
Response:
Reasoning:
We will utilize a Gaussian surface that resembles the curved wall of a cylinder, with a radius of 3mm and a length of 1 unit directed parallel to the wire axis.
The charge within this cylinder amounts to 250 x 10⁻⁹ C.
Let E denote the electric field at the curved surface, perpendicular to it.
The total electric flux leaving the curved surface
is calculated as 2π r x 1 x E
or 2 x 3.14 x 3 x 10⁻³ E
According to Gauss's law, the total flux is given by the charge within divided by ε (the charge inside the cylinder being 250 x 10⁻⁹C)
equals 250 x 10⁻⁹ / 2.5 x 8.85 x 10⁻¹² (where ε = 2.5 ε₀ = 2.5 x 8.85 x 10⁻¹²)
resulting in 11.3 x 10³ weber.
Thus,
2 x 3.14 x 3 x 10⁻³ E = 11.3 x 10³
E = 11.3 x 10³ / 2 x 3.14 x 3 x 10⁻³
=.599 x 10⁶ N /C.
Answer:
Explanation:
Provided:
mass of the steel ball 
initial velocity of the ball 
Final velocity of the ball 
(moving upwards)
The impulse given is determined by the change in the momentum of the object.
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Thus, the magnitude of the Impulse is 4 N-s.
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Answer:
The mass will be 4.437 kg
Explanation:
The force constant k is given as 7 N/m
The time period of oscillation T is 5 sec
Thus, angular frequency 
It is known that angular frequency is computed via
Squaring both sides gives us
The mass equals 4.437 kg
