Weight of the object = 35 lbs
F = ma
m = F/a = 35/32 (with acceleration of 32 ft/s²)
m= 1.09
Again applying the same formula,
a = F/m
a= 6/1.09
a= 5.489
Thus, the acceleration is approximately 5.5 ft/s²!!
To calculate the rate, first convert units properly. Since 1 kilogram equals 1,000,000 micrograms, 1.6 kilograms is 1,600,000 micrograms. One week has 604,800 seconds. Therefore, dividing 1,600,000 micrograms by 604,800 seconds gives the rate. Simplifying, this results in 2.65 µg/s. I hope this answers your question.
The infinitesimal charge dQ on a layer with thickness dr is expressed as
dQ = (charge density) × (surface area) × dr
dQ = ρ(r)4πr²dr
∫ dQ = ∫ (a/r)4πr²dr
∫ dQ = 4πa ∫ rdr
Q(r) = 2πar² - 2πa0²
Q = 2πar² (= total charge confined within a spherical surface of radius r)
According to Gauss's Law:
(Flux through surface) = (charge enclosed by surface)/ε۪
(Surface area of sphere) × E = Q/ε۪
4πr²E = 2πar²/ε۪
<span>E = a/2ε۪
I trust my response has been helpful. Thank you for your question! We hope to assist with your future inquiries. Have a great day!
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According to the second law, heat, often called thermal energy, cannot be entirely turned into work.
The second statement is closely tied to this law.
We can conclude that some energy dissipates while some is used for work.
Answer:
0.130
Explanation:
The coefficients of static friction recorded for each trial are listed as follows:
1. 0.053
2. 0.081
3. 0.118
4. 0.149
5. 0.180
6. 0.198
Adding these coefficients together results in: 0.053 + 0.081 + 0.118 + 0.149 + 0.180 + 0.198
= 0.779
Consequently;
the mean coefficient of static friction = 
= 
= 0.12983
The mean coefficient of static friction is 0.130
