A small sphere of radius R is arranged to pulsate so that its radius varies in simple harmonic motion between a minimum of R−x a
1 answer:
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Answer:
The time required is 20 μs
Explanation:
Here is the data provided:
temperature = 20°C = 293 K
radius = 1 cm
atomic mass of air = 29 u
To determine
the duration for air to refill the vacuum space
solution:
We calculate the root mean square velocity of air particles. This can be expressed as:
where m indicates mass, t is temperature, v is speed, and R is the ideal gas constant, which is approximately 8.3145 (kg·m²/s²)/K·mol.
v = ............................1
v =
Resulting in v = 501.99 m/s.
<pNow, to cover the distance of 1 cm,<pThe duration needed for air is calculated as:time taken =
which gives us:
time taken =
so, time taken = 19.92 × seconds = 20μs.
Thus, the required time is 20 μs.
Complete Question
An aluminum "12 gauge" wire measures a diameter of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The electric field E in the wire varies over time as E(t)=0.0004t2−0.0001t+0.0004 newtons per coulomb, where time is recorded in seconds.
At time 5 seconds, I = 1.2 A.
We need to find the charge Q traveling through a cross-section of the conductor from time 0 to time 5 seconds.
Answer:
The charge is
Explanation:
The question indicates that
The wire’s diameter is
The radius of the wire is
Aluminum's resistivity is
The electric field variation is described as
The charge is effectively given by the equation
Where A is the area expressed as
Thus,
Therefore
By substituting values
The question states that t = 5 seconds