Clarification:
Let T signify the pendulum's period. The time's SI unit is seconds (s).
It is influenced by the length of the pendulum, l, and the gravitational acceleration, g.
The SI units for gravitational acceleration, g, and pendulum length, l, are m/s² and m, respectively.
Dividing m by m/s² produces s². Taking the square root of s² results in s, which is the SI unit for the pendulum's period.
Thus,
This concludes the solution we sought.
Answer:
The system's energy amounts to 15 J.
Explanation:
Given that,
Energy E = 2.5 J
Amplitude = 10 cm
The spring constant needs to be computed.
Using the formula for the mechanical energy of the system,
Substituting the values into the formula:
If the block is swapped out for one with double the original mass,
Amplitude = 6 cm
We need to find the energy
Using the mechanical energy formula,
Substituting into the formula:
Thus, the system’s energy is 15 J.
Answer:
20.353125 V
Explanation:
m = Mass of proton = 
q = Charge of proton = 
= Velocity of proton at point A = 50 km/s
= Velocity of proton at point B = 80 km/s
The relationship derived from energy conservation is as follows:
The determined potential difference is 20.353125 V
Answer:
Lower than
Explanation:
When the cube is placed on the raft, the displaced water equals the combined weight of both the cube and raft. In contrast, when submerged in water, the displaced water corresponds to the raft's weight plus the cube's volume. Since the cube's volume is smaller than what is needed to displace its weight with water, the water level is lower.
Response:
Reasoning:
We will utilize a Gaussian surface that resembles the curved wall of a cylinder, with a radius of 3mm and a length of 1 unit directed parallel to the wire axis.
The charge within this cylinder amounts to 250 x 10⁻⁹ C.
Let E denote the electric field at the curved surface, perpendicular to it.
The total electric flux leaving the curved surface
is calculated as 2π r x 1 x E
or 2 x 3.14 x 3 x 10⁻³ E
According to Gauss's law, the total flux is given by the charge within divided by ε (the charge inside the cylinder being 250 x 10⁻⁹C)
equals 250 x 10⁻⁹ / 2.5 x 8.85 x 10⁻¹² (where ε = 2.5 ε₀ = 2.5 x 8.85 x 10⁻¹²)
resulting in 11.3 x 10³ weber.
Thus,
2 x 3.14 x 3 x 10⁻³ E = 11.3 x 10³
E = 11.3 x 10³ / 2 x 3.14 x 3 x 10⁻³
=.599 x 10⁶ N /C.
