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mash
3 months ago
10

A rock has mass 1.80 kg. When the rock is suspended from the lower end of a string and totally immersed in water, the tension in

the string is 12.8 N. What is the smallest density of a liquid in which the rock will float?
Physics
1 answer:
inna [3.1K]3 months ago
4 0

Response:

3644.63 kg/m^3

Reasoning:

The mass of the rock is m = 1.80 kg

The weight of the rock when submerged in water is 12.8 N

The weight of the rock in water equals the weight in air minus the buoyant force from the water

The buoyant force in water can be calculated as 1.8 x 9.8 - 12.8 = 17.64 - 12.8 = 4.84 N

Volume multiplied by the density of water times g equals 4.84

V x 1000 x 9.8 = 4.84

Thus, V = 4.939 x 10^-4 m^3

For the rock to be able to float in a fluid

The buoyant force acting on the rock from the liquid should equal the weight of the rock

V x density of liquid x g = 1.80 x g

Therefore, the density of the liquid is 1.80 / (4.939 x 10^-4) = 3644.63 kg/m^3

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The magnitude of the Poynting vector of a planar electromagnetic wave has an average value of 0.939 W/m2. The wave is incident u
Yuliya22 [3333]

Answer:

The total energy can be expressed as T = 169.02 \ J

Explanation:

The problem states that

The Poynting vector, which measures energy flux, equals k = 0.939 \ W/m^2

The rectangle's length is represented by l = 1.5 \ m

The width of the rectangle is w = 2.0 \ m

The duration considered is t = 1 \ minute = 60 \ s

Mathematically, the overall electromagnetic energy incident on the area is given by

T = k * A * t

where A denotes the area of the rectangle, calculated as

A= l * w

By plugging in the respective values

A= 2 * 1.5

A= 3 \ m^2

Again substituting values

T = 0.939 * 3 * 60

T = 169.02 \ J

5 0
3 months ago
An electric buzzer is activated, then sealed inside a glass chamber. When all of the air is pumped out of the chamber, how is th
ValentinkaMS [3465]
The intensity of the sound increases because sound waves are mechanical waves, meaning they cannot move through a vacuum and require a medium to propagate.
4 0
3 months ago
You are designing a spacecraft intended to monitor a human expedition to Mars (mass 6.42×1023kg, radius 3.39×106m). This spacecr
Softa [3030]
The height is h = 17 10⁶ meters above the surface of Mars. To determine this, we apply Newton's second law according to the universal law of gravitation, represented by F = m a. The centripetal acceleration a is expressed as v² / r. Applying the gravitational force we have G m M / r² = m v² / r. Given that the speed of the object remains constant, we derive v from d / t, where d is the circumference and t is the orbital period. Substituting gives us d = 2π r and v = 2π r / T. Replacing these values leads to the equation G M / r² = (4π² r² / T) / r, so r³ = G M T² / 4π². Converting time into SI units, T = 24.66 h converts to 88776 seconds. Ultimately, the computed value of r is 2,045 10⁶ m, and after subtracting Mars’ radius of 3.39 10⁶ m, we find the height h to be 17 10⁶ m.
3 0
2 months ago
1200 N-m of torque is used to drive a gear (A) of diameter 25 cm, which in turn drives another gear (B) of diameter 52 cm. What
Ostrovityanka [3204]

Response:

2.5kN.m

Details:

Torque relates directly to the pitch diameter

= Ta/Tb= Da/Db

For 120/Tb= 0.25/0.5

This gives Tb= 2.469kN.m, roughly 2.5kN.m


8 0
3 months ago
Read 2 more answers
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