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Masja
1 day ago
5

An old 0.500 L lecture bottle of triethylamine (N(CH₂CH₃)₃) was found in a lab and needed for a synthesis reaction. A pressure r

egulator indicated a pressure of 18.5 psi, and the lab was at room temperature (25.0°C). What mass of vaporized triethylamine in grams was left in the lecture bottle?
Chemistry
1 answer:
lorasvet [960]1 day ago
6 0

Mass of vaporized triethylamine: 2.606 g

Further explanation

Given

0.5 L of triethylamine

P = 18.5 psi

T = 25 °C

Required

the mass of vaporized triethylamine

Solution

Conversion:

P 18.5 psi = 1.26 atm

T = 25 + 273 = 298 K

Using the ideal gas law:

PV=nRT

n = PV/RT

Insert the values:

n = (1.26 atm x 0.5 L) /(0.08205 x 298)

n = 0.0258

With the molecular weight of triethylamine being 101 g/mol, we find:

mass of triethylamine:

= n x MW

= 0.0258 x 101 g/mol

= 2.606 g

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Response:

9.606 g

Clarification:

Step 1: Write the balanced combustion equation

C₂H₆O(l) + 3 O₂(g) → 2 CO₂(g) + 3 H₂O(g)

Step 2: Determine the moles for 11.27 g of H₂O

The molar mass of H₂O is 18.02 g/mol.

11.27 g × (1 mol/18.02 g) = 0.6254 mol

Step 3: Find the moles of C₂H₆O that produced 0.6254 moles of H₂O

The ratio of C₂H₆O to H₂O is 1:3. Thus, the moles of C₂H₆O are 1/3 × 0.6254 mol = 0.2085 mol

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7 0
10 days ago
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Unit conversion is needed from miles to meters since the speed is given in meters per second.

1 mile = 1609.34 meters

Thus, 24900mile(\frac{1609.34meter}{mile})

= 40072566 meters

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Rearranged for time, that gives: time=\frac{distance}{speed}

Inserting the values:

time=\frac{40072566meter}{2.988*10^8\frac{meter}{second}}

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8 0
4 days ago
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Sugar, being a covalent compound, has bonds where electrons are shared unevenly, creating slight positive and negative charges. This characteristic allows sugar to interact with the polar ends of water, facilitating its dissolution. Therefore, it can be stated that sugar dissolves in water due to both substances being polar.

In summary, water is capable of dissolving most polar or ionic substances, as seen with sugar and salt.

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