The speed of light in a vacuum is 2.998 × 10 8 8 m/s. How long does it take for light to circumnavigate the Earth, which has a c

n equals 1.3 x 10¹⁸ photons. First, we calculate the energy released over the specified duration: E = Pt, where, E = Energy =?, P = Power = 4 mW = 0.004 W, t = time = 115 s. Thus, E = (0.004 W)(115 s), resulting in E = 0.46 J. This energy can be expressed in terms of photons: E = nhc/λ, where, n = Number of photons =?, h = Planck's Constant = 6.626 x 10⁻³⁴ J.s, c = speed of light = 3 x 10⁸ m/s, λ = wavelength of the light = 5650 x 10⁻¹⁰ m. Thus, 0.46 J = n(6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(5650 x 10⁻¹⁰ m), leading to n = (0.46 J)/(3.5 x 10⁻¹⁹ J), culminating in n = 1.3 x 10¹⁸ photons.

The result will be 100.60 because we are adding to the atmosphere, which connects to the lubricator, and then it turns, resulting in 100.60.

The answer is A. Product molecules.

Explanation:

The rate at which gases effuse is inversely related to the square root of their molar masses.

In this case, half of the helium (1.5 L) passed through the membrane in 24 hours. Therefore, we can calculate the effusion rate of He gas as follows.

         

            = 0.0625 L/hr

Given that the molar mass of He is 4 g/mol and for it is 32 g/mol.

Now,

   

                               = 2.83

Thus, the effusion rate of

                       =

          Rate of = 0.022 L/hr.

This implies that 0.022 L of gas will effuse in one hour.

Consequently, to find the duration needed for 1.5 L of gas to effuse, we calculate as follows.

         

                = 68.18 hours

Thus, we can conclude that it will require 68.18 hours for half of the oxygen to effuse through the membrane.

I think the right choice is C. Coal, as it's utilized in making a multitude of products across the globe. I trust this information is useful to you.:)