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Ghella
1 day ago
15

You have a racemic mixture of d-2-butanol and l-2-butanol. the d isomer rotates polarized light by +13.5∘. what is the rotation

of the polarization of light of your mixture? express your answer in degrees.
Chemistry
1 answer:
Anarel [852]1 day ago
8 0
The L- isomer serves as the enantiomer of the D- isomer, and given that the optical rotation of the D- isomer is + 13.5°, the L- isomer's optical rotation will have the same magnitude but an opposite sign, resulting in -13.5°.

Thus, the rotation of the racemic mixture will be equal to 0°.


- This occurs because a racemic mixture contains equal proportions of both enantiomers.
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a nurse practitioner orders Medrol to be given 1.5 mg/kg of body weight. if a child weighs 72.6lb and the available stock of Med
KiRa [971]
The amount to administer to the child is 2,469 mL.
To convert to kilograms (kg), the child's weight in pounds (lb) is multiplied by 0.45359237: m(child) = 72.6 · 0.045359237 = 32.93 kg.
To find m(Medrol), the child's mass in kilograms is multiplied by 1.5 mg/kg.
Thus, m(Medrol) = 32.93 kg · 1.5 mg/kg = 49.39 mg.
The concentration of Medrol is d(Medrol) = 20.0 mg/mL.
To find the volume of Medrol needed, use V(Medrol) = m(Medrol) ÷ d(Medrol).
So, V(Medrol) = 49.39 mg ÷ 20 mg/mL = 2,469 mL.

8 0
7 days ago
Calculate the mass, in grams, of a single tellurium atom (mte = 127.60 amu ).
castortr0y [923]

1 atomic mass unit (amu) represents the mass of an atom or is used to measure mass on an atomic scale. It is also referred to as a dalton, abbreviated as Da, while atomic mass unit is indicated as amu.

1 amu can be translated into grams as follows:

1 amu = 1.6 * 10^-2^4 g

Mass of Te = 127.6 amu

For conversion into grams:

M = (127.6 ) * 1.6 * 10^-2^4 g

M = 204.16 * 10^-2^4 g

Therefore, the mass of Te is 204.16 * 10^-2^4 g

8 0
8 days ago
Read 2 more answers
HCl(aq)+NaOH(aq)→NaCl(aq)+H2O(l)
Alekssandra [968]

Answer:

Quantity of H_{2}O generated will be reduced to fifty percent of its initial amount.

Explanation:

Equilibrium reaction: HCl+NaOH\rightarrow NaCl+H_{2}O

In accordance with the balanced equation, 1 mol of HCl interacts with 1 mol of NaOH leading to the formation of 1 mol of H_{2}O

<pif the="" quantities="" of="" reactants="" and="" hcl="" are="" diminished="" by="" half="" it="" results="" in:="">

0.5 mol of HCl interacting with 0.5 mol of NaOH yielding 0.5 mol of H_{2}O.

Consequently, it is clear that the total of H_{2}O produced will be halved if the quantities of the reactants are halved.

</pif>
5 0
14 days ago
A student is given a sample of a blue copper sulfate hydrate. He weighs the sample in a dry covered porcelain crucible and got a
KiRa [971]

Answer:

There are 5.5668 moles of water for every mole of CuSO₄.

Explanation:

The mass of anhydrous CuSO₄ is:

23.403g - 22.652g = 0.751g.

mass of crucible + lid + CuSO₄ - mass of crucible + lid

Given that the molar mass of CuSO₄ is 159.609g/mol, we calculate the moles:

0.751g ×\frac{1mol}{159,609g} = 4.7052x10⁻³ moles CuSO₄

The mass of water in the initial sample is:

23.875g - 0.751g - 22.652g = 0.472g.

mass of crucible + lid + CuSO₄ hydrate - CuSO₄ - mass of crucible + lid

As the molar mass of H₂O is 18.02g/mol, we find the moles:

0.472g ×\frac{1mol}{18,02g} = 2.6193x10⁻² moles H₂O

The mole ratio of H₂O to CuSO₄ is:

2.6193x10⁻² moles H₂O / 4.7052x10⁻³ moles CuSO₄ = 5.5668

This indicates there are 5.5668 moles of water per mole of CuSO₄.

I hope this is helpful!

5 0
8 days ago
When performing a flame test using the method described in the manual, you complete the flame test of KNO3 and find a yellow col
Tems11 [846]

Answer:

The nichrome wire has contaminants.

The sample solution might be tainted.

Explanation:

If the nichrome wire is contaminated, sodium impurities could be causing the yellow flame. The wire is initially placed in the flame without the sample to check for such impurities.

The testing solution could also be contaminated, causing it to display a color different from the anticipated shade of the test ion.

7 0
10 days ago
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