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sveta
2 months ago
8

A careless laboratory technician wants to prepare 200.0 mL of a 0.025 m HCl(aq) solution but uses a volumetric flask of vol- ume

250.0 mL by mistake. (a) What would the pH of the desired solution have been? (b) What will be the actual pH of the solution as prepared?
Chemistry
1 answer:
KiRa [2.9K]2 months ago
4 0

Answer:

a) 0.9030 b) 1

Explanation:

The pH is determined by calculating the negative logarithm of the hydrogen ion concentration of a solution. When HCl dissociates in water, it produces 1 mole of hydrogen ion concentration; similarly, if 0.025 m of HCl dissociates in water, it yields 0.025 moles of hydrogen ions.

For HCl's molarity in a 200 mL solution = moles / volume in liters = 0.025 / ( 200/1000) = 0.125 M

pH = log base 10 ( 0.125^ -1) = 0.903

Calculating the molarity of HCl in 250 mL = 0.025 / (250/1000) = 0.1 M

pH = log base 10 ( 0.1^-1) = 1

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