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DENIUS
1 month ago
6

Consider butter (density= 0.860 g/mL) and sand (density= 2.28 g/mL). If 1.00 mL of butter were mixed with 1.00 mL of sand and mi

xed as thoroughly as possible what would be the density of the resulting mixture?
Chemistry
1 answer:
Anarel [2.9K]1 month ago
6 0

The mixture’s density is 1.57 g/cm³.


Step 1: Determine the mass of the butter.


\text{Mass} = \text{1.00 cm}^{3 } \times \frac{\text{0.680 g} }{\text{1 cm}^{3 }} = \text{0.860 g}\\

Step 2: Determine the mass of the sand.


\text{Mass} = \text{1.00 cm}^{3 } \times \frac{\text{2.28 g} }{\text{1 cm}^{3 }} = \text{2.28 g}\\

Step 3: Determine the density of the mixture.

Total mass = 0.860 g + 2.28 g = 3.14 g.

Total volume = 1 cm³ + 1 cm³ = 2 cm³

\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{\text{3.14 g} }{\text{2 cm}^{3 }} = \textbf{1.57 g/cm}{^{3}\\

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Which of the following statements is true about the relationships between photon energy, wavelength, and frequency?
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Answer: The Answer is A.

Explanation:

The energy of a photon is directly related to its electromagnetic frequency, meaning it is inversely related to the wavelength. A higher frequency results in greater energy for the photon. Conversely, a longer wavelength corresponds to lower energy levels.

Hope this Helps!

8 0
1 month ago
Acetone major species present when dissolved in water
Alekssandra [3086]

The compound is acetone ( CH₃-CO-CH₃)


Explanation:


1) Acetone is represented as CH₃-CO-CH₃.


2) This is a molecule formed by covalent bonds.


3) When it dissolves, compounds with covalent bonds remain as individual molecules, indicating that the primary species in the solution are the molecules themselves, which are surrounded (solvated) by water molecules.


In contrast, ionic compounds ionize. For example, when NaCl dissolves in water, it completely breaks down into ions, hence the predominant species are the ions Na⁺ and Cl⁻, rather than the NaCl formula.


This leads to the conclusion that: when acetone dissolves in water, the primary components are the acetone molecules (there is no need to mention that water molecules are in the solution, as that isn't the question's focus).



3 0
1 month ago
Liquid nitrogen has a density of 0.807 g/ml at –195.8 °c. if 1.00 l of n2(l) is allowed to warm to 25°c at a pressure of 1.00 at
castortr0y [3046]
Step 1: Convert density from g/mL to g/L; 0.807 g/mL is equivalent to 807 g/L. Step 2: Calculate Moles of N₂; Density = Mass / Volume, or Mass = Density × Volume. Plugging in values, Mass = 807 g/L × 1 L gives us Mass = 807 g. Similarly, Moles = Mass / M.mass, which leads to Moles = 807 g / 28 g.mol⁻¹, giving us Moles = 28.82 moles. Step 3: Apply the Ideal Gas Law to determine Volume of gas occupied; P V = n R T, thus V = n R T / P. Remember to convert temperature to Kelvin (25 °C + 273 = 298 K). Hence, V = (28.82 mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 298 K) ÷ 1 atm, resulting in V = 704.76 L.
8 0
1 month ago
How many moles of carbon are in 7.87x10^7 carbon molecules?
Anarel [2989]
There are 6.022*10^23 molecules in one mole of carbon. To find out how many moles correspond to 7.87*10^7 molecules, we let the number of moles be represented by ‘x’. From this, we establish a ratio: 1 mole corresponds to 6.022*10^23 molecules, while x moles correspond to 7.87*10^7 molecules. Using cross multiplication, we derive x = 7.87*10^7 / 6.022*10^23, leading to the conclusion that x = 1.3*10^-16.
6 0
1 month ago
How many atoms are in 80.45 g of magnesium?
VMariaS [2998]

Greetings!

To determine the number of atoms present in 80.45 grams of magnesium, we require Avogadro's number and the weight of a single mole of magnesium.

Avogadro's number is 6.02 x 10^23 atoms, and the mass of one mole of magnesium is 24.31 grams.

1. First, divide by the weight of one mole of magnesium

80.45 / 24.31 ≈ 3.309 moles (rounded to appropriate significant figures)

2. Multiply the number of moles by Avogadro's number

3.309 x (6.02 x 10^23) ≈ 1.99 x 10^24 (rounded to appropriate significant figures)

Thus, in 80.45 grams of magnesium, there are approximately 1.99 x 10^24 atoms.

8 0
16 days ago
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