Answer:
Oversight of weights and measures ensures correct evaluations of goods and services so that everyone receives a fair exchange in the marketplace. It also acts as a deterrent, promoting honesty among traders.
Explanation:
Answer:
The molality is 1.15 m.
Molality is calculated by dividing the number of moles of solute by the kilograms of solvent, which in this case is water.
Calculate moles of H₂SO₄ from molarity:
C = n/V → n = C × V = 6.00 mol/L × 0.048 L = 0.288 moles
Mass of solvent (water) based on density:
m = ρ × V = 1.00 kg/L × 0.250 L = 0.250 kg
Therefore, molality is:
m = moles/solvent mass = 0.288 moles / 0.250 kg = 1.15 m
Answer:
The molar mass of the gas is 36.25 g/mol.
Explanation:
- To determine this, we utilize the mathematical relationship:
ν = 
Where, ν represents the speed of light in a gas (ν = 449 m/s),
R denotes the universal gas constant (R = 8.314 J/mol.K),
T stands for the temperature of the gas in Kelvin (T = 20 °C + 273 = 293 K),
M is the molar mass of the gas in (Kg/mol).
ν = 
(449 m/s) = √(3(8.314 J/mol.K)(293 K)/M,
by squaring both sides:
(449 m/s)² = (3(8.314 J/mol.K)(293 K))/M,
thus M = (3(8.314 J/mol.K)(293 K)/(449 m/s)² = 7308.006/201601 = 0.03625 Kg/mol.
Thus, the molar mass of the gas is 36.25 g/mol.
Answer :
The percentage ionic character (%IC) equals 10%, indicating the bond is mostly covalent with slight polarity.
Percent Ionic Character:
This reflects the fraction of ionic nature within a polar covalent bond. The formula for %IC (% ionic character) is:

Here, Xa is the electronegativity of atom A and Xb is that of atom B.
Given: The compound is TiAl₃.
Electronegativity of Ti = 2.0
Electronegativity of Al = 1.6 (as shown in the provided image)
Substitute these values into the formula:



The value of e⁻¹ equals 0.90.
Therefore, percent ionic character = (1 - 0.90) × 100
Percent Ionic Character = 10%
Because the % IC is only 10%, which is relatively low, the bond is classified as covalent with minimal polarity.
The balanced chemical equation for the neutralization of HCl with
is:

Given weight of
= 5g
Moles of
= 
Volume of HCl solution = 
Assuming the density of the solution is 1.0 g/mL
Mass of HCl solution = 50 g
Overall mass of the solution = 50 g + 5 g = 55 g
To find the heat of neutralization, we calculate:
Q = m C ΔT
where m equals the mass of the solution = 55 g
C represents the specific heat capacity of the solution = 4.184
ΔT signifies the temperature change = 6.8 K = (6.8 - 273) C = -266.2

The enthalpy of neutralization per mole of 
= 