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Valentin
2 months ago
15

A gas is enclosed in a cylinder fitted with a light frictionless piston and maintained at atmospheric pressure. When 254 kcal of

heat is added to the gas, the volume is observed to increase slowly from 12.0 m3 to 16.2 m3 . Part A Calculate the work done by the gas. Express your answer with the appropriate units. W = nothing nothing Request Answer Part B Calculate the change in internal energy of the gas. Express your answer with the appropriate units. ΔU = nothing nothing
Physics
1 answer:
serg [3.5K]2 months ago
4 0

Answer:

Explanation:

The atmospheric pressure is P = 10⁵ N/m²

The volume change is Δ V = 16 - 12 = 4 m³

Work done by the gas at constant pressure can be expressed as:

W = P Δ V

Substituting in values:

Work done = 10⁵ x 4

W = 4 x 10⁵ J.

Part B) The heat added is Q = 254 x 10³ cals

= 254 x 4.2 x 10³ J

= 10.66 x 10⁵ J

According to the first law of thermodynamics:

Q = Δ E + W

Where Q denotes heat energy added, Δ E represents the increase in internal energy, and W signifies the work performed by the gas.

Substituting the known values:

10.66 x 10⁵ = Δ E + 4 x 10⁵

Therefore, Δ E = 6.66 x 10⁵ J.

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