Answer:
Explanation:
The atmospheric pressure is P = 10⁵ N/m²
The volume change is Δ V = 16 - 12 = 4 m³
Work done by the gas at constant pressure can be expressed as:
W = P Δ V
Substituting in values:
Work done = 10⁵ x 4
W = 4 x 10⁵ J.
Part B) The heat added is Q = 254 x 10³ cals
= 254 x 4.2 x 10³ J
= 10.66 x 10⁵ J
According to the first law of thermodynamics:
Q = Δ E + W
Where Q denotes heat energy added, Δ E represents the increase in internal energy, and W signifies the work performed by the gas.
Substituting the known values:
10.66 x 10⁵ = Δ E + 4 x 10⁵
Therefore, Δ E = 6.66 x 10⁵ J.