The city evaluates the continuous increase of carbon monoxide from different origins each year. According to calculations, in the year "C: 2019"<span> (rounded to the closest whole number), the concentration of CO will surpass the allowed threshold.
If this is not correct, feel free to inform me and I will find out the right answer. However, I am confident this is accurate.:) </span>
Answer:
ΔL = MmRgt / (2m + M)
Explanation:
The system starts from rest, so the change in angular momentum correlates directly to its final angular momentum.
ΔL = L − L₀
ΔL = Iω − 0
ΔL = ½ MR²ω
To determine the angular velocity ω, begin by drawing a free body diagram for both the pulley and the block.
For the block, two forces act: the weight force mg downward and tension force T upward.
For the pulley, three forces are present: weight force Mg down, a reaction force up, and tension force T downward.
For the sum of forces in the -y direction on the block:
∑F = ma
mg − T = ma
T = mg − ma
For the sum of torques on the pulley:
∑τ = Iα
TR = (½ MR²) (a/R)
T = ½ Ma
Substituting gives:
mg − ma = ½ Ma
2mg − 2ma = Ma
2mg = (2m + M) a
a = 2mg / (2m + M)
The angular acceleration of the pulley is:
αR = 2mg / (2m + M)
α = 2mg / (R (2m + M))
Finally, the angular velocity after time t is:
ω = αt + ω₀
ω = 2mg / (R (2m + M)) t + 0
ω = 2mgt / (R (2m + M))
Substituting into the previous equations gives:
ΔL = ½ MR² × 2mgt / (R (2m + M))
ΔL = MmRgt / (2m + M)
Answer:
The pressure measured at this moment is 0.875 mPa
Explanation:
Given that,
Flow energy = 124 L/min
Boundary to system P= 108.5 kJ/min
We are tasked with finding the pressure here
Applying the pressure formula
Here, 
Where, v refers to velocity
Insert the values into the equation
Therefore, the pressure at this moment is 0.875 mPa
Answer:
The flux across the cube's surface is 
.
Solution:
According to the details provided:
Cube edge length, a = 8.0 cm = 
.
Volume charge density, 
.
Now,
To find the electric flux:
where
= electric flux
= permittivity of vacuum.
The volume charge density for this scenario is described by:
Cube volume, 
.
Thus,
.
The total charge can be derived from equation (2):
.
.
Now, insert the value of 'q' into equation (1):
.
