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Anastaziya
10 days ago
7

How many ternary strings of length 2 n are there in which the zeroes appear only in odd-numbered positions?

Physics
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The loudness of a sound is inversely proportional to the square of your distance from the source of the sound. if your friend is
Yuliya22 [3333]

Define loudness as L, distance as d, and k as the variation constant. The appropriate equation representing the relationship is:
                    L = k / d^2
For Situation 1,
                    L1 = k / d1^2
For Situation 2,
                    L2 = k / (d1 / 4)^2
To have equal k, it follows that L2 = 16 L1.
Thus, the loudness your friend experiences is 16 times greater than yours.

 
5 0
3 months ago
Read 2 more answers
A BMX bicycle rider takes off from a ramp at a point 2.4 m above the ground. The ramp is angled at 40 degrees from the horizonta
Ostrovityanka [3204]

Answer:

The BMX rider lands 5.4 meters horizontally away from the ramp's end.

Explanation:

The BMX position vector is represented as:

r = (x0 + v0 × t × cos α, y0 + v0 × t × sin α + ½ × g × t²)

Where:

r = position at time t

x0 = initial horizontal position

v0 = initial speed

α = angle of jump

y0 = initial vertical height

g = gravitational acceleration (-9.8 m/s², upward positive)

Refer to the diagram for clarity. At the landing time, the vertical coordinate of the position vector is -2.4 m, measured from the ramp's edge as the origin. Using the vertical component equation for y, one can solve for t, then substitute t to find the horizontal distance.

The vertical position equation:

-2.4 m = 0 + 5.9 m/s × t × sin 40° - ½ × 9.8 m/s² × t²

Rearranged:

0 = -4.9 t² + 5.9 t × sin 40° + 2.4

Solving this quadratic yields:

t = 1.2 seconds

Then, calculate horizontal distance:

x = 0 + 5.9 m/s × 1.2 s × cos 40° = 5.4 m

This means the BMX lands 5.4 meters from the ramp's edge.

Have a great day!

8 0
3 months ago
A graph of the net force F exerted on an object as a function of x position is shown for the object of mass M as it travels a ho
Softa [3030]

The alteration in kinetic energy is \Delta K = 3Fd

Clarification:

According to the work-energy principle, the task performed on an object corresponds to the alteration in its kinetic energy. In mathematical terms:

W=K_f -K_i= \Delta K

where:

W signifies the work performed on the object

K_f denotes the kinetic energy at the end

K_i indicates the kinetic energy at the start

Furthermore, when the force is exerted in line with the object’s motion, the work done is expressed as:

W=F\Delta x

Here,

F represents the force’s magnitude

\Delta x denotes the object’s displacement

In this scenario, the force impacting the object is

F

While the distance moved is the horizontal length traveled, hence

\Delta x = 3d

Consequently, the work accomplished is

W=(F)(3d)=3Fd

Thus, the alteration in kinetic energy amounts to

\Delta K = 3Fd

Learn more about work and kinetic energy:

5 0
2 months ago
help please!! A runner at a speed of 3.5 m/s comes to a stop in 0.15 seconds. What is the deceleration?
Maru [3345]

Answer:

The runner's deceleration is -23.33 \frac{m}{s^{2} }

Given:

Initial speed = 3.5 \frac{m}{s}

Final speed = 0 \frac{m}{s}

Time taken = 0.15 s

To determine:

Deceleration of the runner =?

Used Formula:

Using the first equation of motion,

v = u + at

Where, v = final speed

u = initial speed

a = deceleration

t = duration

Solution:

<pusing the="" first="" equation="" of="" motion="">

v = u + at

Where, v = final speed

u = initial speed

a = deceleration

t = duration

0 = 3.5 + a (0.15)

-3.5 = 0.15 (a)

a = \frac{-3.5}{0.15}

a = -23.33 \frac{m}{s^{2} }

The negative sign indicates that this represents deceleration.

Hence, the deceleration of the runner is -23.33 \frac{m}{s^{2} }

</pusing>
7 0
2 months ago
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