A beaker containing mercury is placed inside a vacuum chamber in a laboratory. the pressure at the bottom of the beaker is 26000

Answer:

1)

2)

Explanation:

Projectile Motion

When an object is projected near the surface of the Earth at an angle to the horizontal, it follows a trajectory known as a parabola. The only force acting on it (ignoring wind resistance) is gravity, affecting the vertical axis.

The height of a projectile can be calculated using

where represents the initial height from ground level, is the vertical component of the initial velocity, and t is the elapsed time.

The vertical speed component is expressed as

1) To proceed, we will determine the initial vertical velocity component since we lack sufficient data to calculate the absolute value of .

The peak height is attained when , which allows us to compute the time to reach that height.

Solving for

Thus, the maximum height reached is

We know this value is equal to 8 meters

Continuing with the calculations for

Substituting known values yields

2) At t=1.505 seconds, the ball is positioned above Julie’s head; we can calculate

Answer:

35.79 meters

Explanation:

We have an archer, and there is a target. Denote the distance between them as d.

The bowman releases the arrow, which travels the distance d at a velocity of 40 m/s until it hits the target. We establish the equation as:

Right after this, the arrow produces a muffled noise, traveling the same distance d at a speed of 340 m/s in time . Thus, we can derive:

.

Consequently, the sound reaches the archer, precisely 1 second post-firing the bow, resulting in:

.

Using this relationship in the distance formula for sound allows us to write:

.

Substituting the value of d from the first equation yields:

.

Now, after some calculations, we can proceed further:

.

Finally, the value is inserted into the initial equation:

Answer: The calorimeter's heat capacity is

Explanation:

This scenario assumes the amount of heat lost by the hot object equals the amount of heat gained by the cold object.

where,

= specific heat capacity of water =

= specific heat capacity of calorimeter =?

= mass of water = 108.7 g

= mass of calorimeter = 108.7 g

= final temperature of the mixture =

= initial temperature of the water =

= initial temperature of calorimeter =

Now substituting all provided values into the formula, we obtain

Hence, the heat capacity of the calorimeter is