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Darya
1 month ago
12

A beaker containing mercury is placed inside a vacuum chamber in a laboratory. the pressure at the bottom of the beaker is 26000

pa. what is the height of the mercury in the beaker? the acceleration of gravity is 9.81 m/s 2 .
Physics
1 answer:
inna [3.1K]1 month ago
5 0
The density of mercury in its liquid form is
\rho = 13.5 g/cm^3=13500 kg/m^3

We understand that the equation determining the pressure at the base of a fluid column can be expressed through Stevin's law
p=\rho g h
where
\rho represents the density of the liquid
g signifies the acceleration due to gravity
h indicates the height of the fluid column

Given that the pressure at the lower section of the beaker is p=26000 Pa, we can manipulate the preceding formula to calculate the height of the mercury column
h= \frac{p}{\rho g}= \frac{26000 Pa}{(13500 kg/m^3)(9.81 m/s^2)}=0.196m = 19.6 cm
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