Answer:
Explanation:
The position of the charge q₁ is established at (0,0)
Meanwhile, the charge q₂ is located at (x₁,0)
Thus, the electric potential energy between these two charges is determined by:
Now, the location of charge q₂ shifts from (x₁,0) to (x₂,y₂). The updated electric potential energy between the charges can be represented as:
According to the work-energy theorem, the alteration in potential energy corresponds to the work performed. This is expressed mathematically as:
Consequently, the work done by the electrostatic force on the moving charge is 
. Therefore, this concludes the solution.
Response:
(b) 10 Wb
Clarification:
Given;
angle of the magnetic field, θ = 30°
initial area of the plane, A₁ = 1 m²
initial magnetic flux through the plane, Φ₁ = 5.0 Wb
The equation for magnetic flux is;
Φ = BACosθ
where;
B denotes the magnetic field strength
A represents the area of the plane
θ is the inclination angle
Φ₁ = BA₁Cosθ
5 = B(1 x cos30)
B = 5/(cos30)
B = 5.7735 T
Next, calculate the magnetic flux through a 2.0 m² section of the same plane:
Φ₂ = BA₂Cosθ
Φ₂ = 5.7735 x 2 x cos30
Φ₂ = 10 Wb
<pHence, the magnetic flux through a 2.0 m² area of the same plane is
10 Wb.Option "b"
Answer:
The kinetic energy is higher for the first cart.
Explanation:
For the second cart, its mass is 2kg and the momentum measured is 10kg m/s, which leads to
resulting in
.
Consequently, the kinetic energy for the 3kg cart ends up as
indicating it is less than that of the 1kg cart so it follows that the first cart possesses greater kinetic energy.
Answer: The resulting speed is
. Option (a) stands as the correct choice. Explanation: Given the context, the potential difference entails calculations linked to speed assessment. If instead accelerated through a different potential difference, the resulting speed will be computed accordingly.
